这题我没做出来
class Solution {
List<List<Integer>> res = new ArrayList<>();
LinkedList<Integer> path = new LinkedList<>();
public List<List<Integer>> findSubsequences(int[] nums) {
backtracking(nums, Integer.MIN_VALUE,0);
return res;
}
public void backtracking(int[] nums,int last, int startIndex){
if(startIndex == nums.length){
if( path.size() >= 2){
res.add(new ArrayList<>(path));
}
return;
}
if(nums[startIndex] >= last){
path.add(nums[startIndex]);
backtracking(nums,nums[startIndex],startIndex + 1);
path.pollLast();
}
if(nums[startIndex] != last){
backtracking(nums,last,startIndex + 1);
}
}
}
class Solution {
private List<Integer> path = new ArrayList<>();
private List<List<Integer>> res = new ArrayList<>();
public List<List<Integer>> findSubsequences(int[] nums) {
backtracking(nums,0);
return res;
}
private void backtracking (int[] nums, int start) {
if (path.size() > 1) {
res.add(new ArrayList<>(path));
}
int[] used = new int[201];
for (int i = start; i < nums.length; i++) {
if (!path.isEmpty() && nums[i] < path.get(path.size() - 1) ||
(used[nums[i] + 100] == 1)) continue;
used[nums[i] + 100] = 1;
path.add(nums[i]);
backtracking(nums, i + 1);
path.remove(path.size() - 1);
}
}
}
两种算法都是每一层如果出现和last相同的元素则