栈与队列相关题目

栈与队列相关题目

class MyQueue {
    
    LinkedList<Integer> stack1;
    LinkedList<Integer> stack2;

    public MyQueue() {
        stack1 = new LinkedList<Integer>();
        stack2 = new LinkedList<Integer>();
    }
    
    public void push(int x) {
        stack1.push(x);
        
    }
    
    public int pop() {
        while (!stack2.isEmpty()) {
            return stack2.pop();
        }


        int len = stack1.size();
        for (int i = 0; i < len; i++) {
            stack2.push(stack1.pop());
        }
        return stack2.pop();
    }
    
    public int peek() {

        while (!stack2.isEmpty()) {
            return stack2.peek();
        }

        int len = stack1.size();
        for (int i = 0; i < len; i++) {
            stack2.push(stack1.pop());
        }
        return stack2.peek();
    }
    
    public boolean empty() {
        return stack1.isEmpty() && stack2.isEmpty();
    }
}

/**
 * Your MyQueue object will be instantiated and called as such:
 * MyQueue obj = new MyQueue();
 * obj.push(x);
 * int param_2 = obj.pop();
 * int param_3 = obj.peek();
 * boolean param_4 = obj.empty();
 */

 栈与队列相关题目

//真正意义上,理解写一个类的方法,也就是深入源码。
//绝对的理解栈和队列的题目,包括交换、反转,这个题目得重点看一下

//单个队列转成栈得写法
class MyStack {
    
    LinkedList<Integer> queue; 

    public MyStack() {
        //这样写错了
        //LinkedList<Integer> queue = new LinkedList<Integer>();
        queue = new LinkedList<Integer>();
    }
    
    public void push(int x) {
        //一个数我不需要交换,两个数我需要交换一次,n个交换n-1次
        int len = queue.size();
        queue.offer(x);
        for (int i = 0; i < len; i++) {
            queue.offer(queue.poll());
        }
    }
    
    public int pop() {
        return queue.poll();
    }
    
    public int top() {
        return queue.peek();
    }
    
    public boolean empty() {
        return queue.isEmpty();
    }
}

/**
 * Your MyStack object will be instantiated and called as such:
 * MyStack obj = new MyStack();
 * obj.push(x);
 * int param_2 = obj.pop();
 * int param_3 = obj.top();
 * boolean param_4 = obj.empty();
 */
 //两个队列得写法
class MyStack {
    Queue<Integer> queue1;
    Queue<Integer> queue2;

    /** Initialize your data structure here. */
        public MyStack() {
        queue1 = new LinkedList<Integer>();
        queue2 = new LinkedList<Integer>();
    }
    
    /** Push element x onto stack. */
    public void push(int x) {
        //一个队列作为辅助队列,很简单额,我服了
        queue2.offer(x);
        while (!queue1.isEmpty()) {
            queue2.offer(queue1.poll());
        }
        Queue<Integer> temp = queue1;
        queue1 = queue2;
        queue2 = temp;
    }
    
    /** Removes the element on top of the stack and returns that element. */
    public int pop() {
        return queue1.poll();
    }
    
    /** Get the top element. */
    public int top() {
        return queue1.peek();
    }
    
    /** Returns whether the stack is empty. */
    public boolean empty() {
        return queue1.isEmpty();
    }
}

 栈与队列相关题目

 

//栈出场,栈是一种逻辑数据结构,可以用数组和链表实现。注意,是逻辑

class Solution {
    public boolean isValid(String s) {
        if (s.isEmpty()) return true;
        Deque<Character> stack = new LinkedList<>();
        for (Character x : s.toCharArray()) {
            if (x == '(') {
                stack.push(')');
            } else if (x == '[') {
                stack.push(']');
            } else if (x == '{') {
                stack.push('}');
            } else if (stack.isEmpty() || x != stack.pop()){
                return false;
            }
        }
        if (stack.isEmpty()) {
            return true;
        } 
        return false;
    }
}


//不能说自己思路不够开阔吧,应该是没有思路、、、
//获取栈首元素后,元素不会出栈stack.peek()
//获取栈首元素后,元素将会出栈stack.pop()

class Solution {
    public boolean isValid(String s) {
        int len = s.length();
        if (len % 2 == 1) return false;
        Map<Character, Character> map = new HashMap<>();
        map.put(')', '(');
        map.put('}', '{');
        map.put(']', '['); 
        Deque<Character> stack = new LinkedList<>();
        for (int i = 0; i < len; i++) {
            char c = s.charAt(i);
            if (map.containsKey(c)) {
                if (stack.isEmpty() || stack.peek() != map.get(c)) {
                    return false;
                } else {
                    stack.pop();
                }
            } else {
                stack.push(c);
            }
        }
        return stack.isEmpty();
    }
}

栈与队列相关题目

 

// class Solution {
//     public String removeDuplicates(String s) {
//         Deque<Character> stack = new LinkedList<>();
//         for (int i = 0; i < s.length(); i++) {
//             char c = s.charAt(i);
//             if (!stack.isEmpty() && c == stack.peek()) {
//                 stack.pop();
//             } else {
//                 stack.push(c);
//             }

//         }
//         Deque<Character> stackTemp = new LinkedList<>();
//         StringBuilder res = new StringBuilder();
//         while (!stack.isEmpty()) stackTemp.push(stack.pop());
//         while (!stackTemp.isEmpty()) res.append(stackTemp.pop());
//         return res.toString();
//     }
// }

//StringBuilder本身就可以作为栈
class Solution {
    public String removeDuplicates(String s) {
        StringBuffer stack = new StringBuffer();
        int top = -1;
        for (int i = 0; i < s.length(); i++) {
            char ch = s.charAt(i);
            if (top >= 0 && stack.charAt(top) == ch) {
                stack.deleteCharAt(top);
                top--;
            } else {
                stack.append(ch);
                top++;
            }
        }
        return stack.toString();
    }
}




// //队列不行哦,获取的是首元素,别想当然
// class Solution {
//     public String removeDuplicates(String s) {
//         Queue<Character> queue = new LinkedList<>();
//         for (int i = 0; i < s.length(); i++) {
//             char c = s.charAt(i);
//             if (!queue.isEmpty() && c == queue.peek()) {
//                 queue.poll();
//             } else {
//                 queue.offer(c);
//             }

//         }
        
//         StringBuilder res = new StringBuilder();
        
//         while (!queue.isEmpty()) res.append(queue.poll());
//         return res.toString();
//     }
// }

栈与队列相关题目

 

class Solution {
    public int evalRPN(String[] tokens) {
        Deque<Integer> stack1 = new LinkedList<>();
        Deque<String> stack2 = new LinkedList<>();
        for (int i = 0; i < tokens.length; i++) {
            String token = tokens[i];
            //判断字符s.charAt(i)内容是否是数字isDigit
            //这是自己写的方法,判断字符串是否是数字
            if (isNumber(token)) {
                stack1.push(Integer.parseInt(token));
            } else {
                stack2.push(token);
            }
            if (!stack2.isEmpty()) {
                int value1 = stack1.pop();
                int value2 = stack1.pop();
                //弹栈是一个操作,所以在if的时候就会执行了,这样多次if就重复了,所以提前弹出来记录。
                String s = stack2.pop();
                if ("+".equals(s)) {
                    int value3 = value1 + value2;
                    stack1.push(value3);
                } else if ("-".equals(s)) {
                    int value3 = value2 - value1;
                    stack1.push(value3);
                } else if ("*".equals(s)) {
                    int value3 = value2 * value1;
                    stack1.push(value3);
                } else {
                    int value3 = value2 / value1;
                    stack1.push(value3);
                }
            }
        }
        return stack1.pop();
    }    

    public static boolean isNumber(String token) {
        return !("+".equals(token) || "-".equals(token) || "*".equals(token) || "/".equals(token));
    }
    
}
// class Solution {
//     public int evalRPN(String[] tokens) {
//         Deque<Integer> stack = new LinkedList<Integer>();
//         int n = tokens.length;
//         for (int i = 0; i < n; i++) {
//             String token = tokens[i];
//             if (isNumber(token)) {
//                 stack.push(Integer.parseInt(token));
//             } else {
//                 int num2 = stack.pop();
//                 int num1 = stack.pop();
//                 switch (token) {
//                     case "+":
//                         stack.push(num1 + num2);
//                         break;
//                     case "-":
//                         stack.push(num1 - num2);
//                         break;
//                     case "*":
//                         stack.push(num1 * num2);
//                         break;
//                     case "/":
//                         stack.push(num1 / num2);
//                         break;
//                     default:
//                 }
//             }
//         }
//         return stack.pop();
//     }

//     public boolean isNumber(String token) {
//         return !("+".equals(token) || "-".equals(token) || "*".equals(token) || "/".equals(token));
//     }
// }

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