要求:通过二叉树的前序和中序遍历序列构建一颗二叉树
代码如下:
1 struct TreeNode { 2 int val; 3 TreeNode *left; 4 TreeNode *right; 5 TreeNode(int x): val(x),left(NULL), right(NULL) {} 6 }; 7 8 typedef vector<int>::iterator Iter; 9 TreeNode *buildTree(vector<int> &preorder, vector<int> &inorder) 10 { 11 return buildTreeRecur(preorder.begin(), preorder.end(), inorder.begin(), inorder.end()); 12 } 13 14 TreeNode *buildTreeRecur(Iter pstart, Iter pend, Iter istart, Iter iend) 15 { 16 if(pstart == pend || istart == iend) 17 return NULL; 18 int ival = *pstart; 19 Iter ipos = find(istart, iend, ival); 20 TreeNode *res = new TreeNode(ival); 21 res->left = buildTreeRecur(pstart + 1, pstart+1+(ipos-istart), istart, ipos); 22 res->right = buildTreeRecur(pstart+1+(ipos-istart), pend, ipos+1, iend); 23 return res; 24 }