我如何在以下jdbctemplate示例中指定’age’参数的值？

String sql = "SELECT * FROM CUSTOMER where age = ? ";

    List<Customer> customers = new ArrayList<Customer>();
    JdbcTemplate jdbcTemplate = new JdbcTemplate(dataSource);

    List<Map> rows = jdbcTemplate.queryForList(sql);
    for (Map row : rows) {
        Customer customer = new Customer();
        customer.setCustId((Long)(row.get("CUST_ID")));
        customer.setName((String)row.get("NAME"));
        customer.setAge((Integer)row.get("AGE"));
        customers.add(customer);
    }

return customers;

解决方法:

您可以使用参数作为参数的queryForList()方法,例如：

List<Map<String, Object>> rows = jdbcTemplate.queryForList(sql, theAge);    

学习阅读API文档(以及一般文档).这就是你学习的方式.