CCPC网络赛
一场笔试
刷三题
总结复盘最近所学的知识。
看了八章和第九章的一部分。
一题leetcode
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Codec { public: // Encodes a tree to a single string. string serialize(TreeNode* root) { string ans = ""; if(root == NULL) return ans; queue<TreeNode*> Q; Q.push(root); while(!Q.empty()){ TreeNode *T = Q.front(); Q.pop(); if(T != NULL){ ans += to_string(T -> val); ans += "*"; Q.push(T -> left); Q.push(T -> right); } else ans += "NULL*"; } cout << "str " << ans << endl; return ans; } // Decodes your encoded data to tree. void dfs(TreeNode * &root,string &data,int &l){ queue<TreeNode**>Q; Q.push(&root); while(!Q.empty()){ TreeNode **T = Q.front(); Q.pop(); int len = 0; if(data[l] == ‘N‘){ *T = NULL; l += 5; } else { int s = l; while(l < data.size() && ((data[l] >= ‘0‘ && data[l] <= ‘9‘) || data[l] == ‘-‘)){ l ++; len ++; } string str = data.substr(s,len); int n = atoi(str.c_str()); while(l < data.size() && data[l] == ‘*‘) ++ l; *T = (TreeNode *)malloc(sizeof(TreeNode)); (*T) -> val = n; (*T) -> left = (*T) -> right = NULL; Q.push(&((*T) -> left)); Q.push(&((*T) -> right)); } } return ; } TreeNode* deserialize(string data) { TreeNode *root = NULL; if(data.size() == 0) return root; int l = 0; dfs(root,data,l); return root; } }; // Your Codec object will be instantiated and called as such: // Codec ser, deser; // TreeNode* ans = deser.deserialize(ser.serialize(root));