题目
Given an integer n, return true if it is a power of three. Otherwise, return false.
An integer n is a power of three, if there exists an integer x such that n == 3x.
Example 1:
Input: n = 27
Output: true
Example 2:
Input: n = 0
Output: false
Example 3:
Input: n = 9
Output: true
Example 4:
Input: n = 45
Output: false
Constraints:
-2^31 <= n <= 2^31 - 1
Follow up: Could you solve it without loops/recursion?
代码
class Solution {
public:
bool isPowerOfThree(int n) {
int base = log10(n*1.0) / log10(3.0);
if(pow(3, double(base)) == n && n)
return true;
else
return false;
}
};
附加问题正好是:可以不用循环和递归实现吗?
然而我的实现貌似是最粗暴简单的解法,效率超出了排行榜233333