//1
#define MAXN 720
struct HP
{
	int len,s[MAXN];
	HP()
	{
		memset(s,0,sizeof(s));
		len=1;
	}
	HP operator =(const char *num)
	{
		len=strlen(num);
		for(int i=0;i<len;i++) s[i]=num[len-i-1]-‘0‘;
	}
	HP operator =(int num)
	{
		char s[MAXN];
		sprintf(s,"%d",num);
		*this=s;
		return *this;
	}
	HP(int num) { *this=num;}
	HP(const char*num) {*this=num;}
	string str()const
	{
		string res="";
		for(int i=0;i<len;i++) res=(char)(s[i]+‘0‘)+res;
		if(res=="") res="0";
		return res;
	}
	HP operator +(const HP& b) const
	{
		HP c;
		c.len=0;
		for(int i=0,g=0;g||i<max(len,b.len);i++)
		{
			int x=g;
			if(i<len) x+=s[i];
			if(i<b.len) x+=b.s[i];
			c.s[c.len++]=x%10;
			g=x/10;
		}
		return c;
	}
	void clean()
	{
		while(len > 1 && !s[len-1]) len--;
	}
	HP operator += (const HP& b)
	{
		*this = *this + b;
		return *this;
	}
};

istream& operator >>(istream &in, HP& x)
{
	string s;
	in >> s;
	x = s.c_str();
	return in;
}

ostream& operator <<(ostream &out, const HP& x)
{
	out << x.str();
	return out;
}
//2
struct BigNum{
    char str[maxn];     //数字反着存方便运算
    int len;

    BigNum():len(0){
        memset(str, 0, sizeof str);
    }

    BigNum operator+(BigNum &num)
    {
        BigNum ret;
        for(int i=0, g=0; g || i<max(len, num.len); i++){
            int ts = g;
            if(i<len) ts+=(int)str[i]-‘0‘;
            if(i<num.len) ts+=(int)num.str[i]-‘0‘;
            g = ts/10;
            ret.str[ret.len++] = ts%10+‘0‘;
        }
        ret.str[ret.len] = ‘\0‘;
        return ret;
    }

    BigNum operator+(int n)
    {
        BigNum num, ret;
        sprintf(num.str, "%d", n);
        num.len = strlen(num.str);
        for(int i=0; i<num.len/2; i++){
            swap(num.str[i], num.str[num.len-i-1]);
        }
        ret = num+*this;
        return ret;
    }

    BigNum operator=(char c[]){
        BigNum ret;
        ret.len = strlen(c);
        for(int i=ret.len-1; i>=0; i--){
            ret.str[i] = c[i];
        }
        ret.str[len] = ‘\0‘;
        return ret;
    }

    BigNum operator=(int num){
        sprintf(this->str, "%d", num);
        this->len = strlen(this->str);
        for(int i=0; i<this->len/2; i++){
            swap(this->str[i], this->str[this->len-i-1]);
        }
        return *this;
    }
};

ostream& operator <<(ostream &out, const BigNum& x){
    for(int i=x.len-1; i>=0; i--){
        out << x.str[i];
    }
    return out;
}

istream& operator >>(istream &in, BigNum& x){
    in >> x.str;;
    x.len = strlen(x.str);
    for(int i=0; i<x.len/2; i++){
        swap(x.str[i], x.str[x.len-i-1]);
    }
    return in;
}

Oracle SQL Developer 连接数据库如何对应数据库配置文件,布布扣,bubuko.com

Oracle SQL Developer 连接数据库如何对应数据库配置文件