【C/C++学院】0829-位容器multimapmutisetString/算法函数兰不达表达式以及类重载/GPU编程

位容器multimapmutisetString

Multiset

#include <set>
#include <iostream>

using namespace std;

void mainA()
{
	multiset<int> myset;
	myset.insert(100);
	myset.insert(101);
	myset.insert(100);
	myset.insert(103);
	myset.insert(100);

	auto pfind = myset.find(101);
	std::cout << *pfind << std::endl;

	auto allfind = myset.equal_range(100);
	//找到红黑树的链表节点,遍历所有的元素


	//find链表的头结点,second最后一个空节点,遍历所有的元素
	for (auto it = allfind.first; it != allfind.second;it++)
	{
		cout << *it << endl;
	}

	cin.get();
}

Multimap

#include <iostream>
#include <map>
#include <string>

using namespace std;

void main2()
{
	multimap<string, string> mymap;
	mymap.insert(pair<string, string>("yincheng", "a"));
	mymap.insert(pair<string, string>("yincheng1", "b"));
	mymap.insert(pair<string, string>("yincheng", "c"));
	mymap.insert(pair<string, string>("yincheng", "d"));

	auto ib = mymap.begin();
	auto ie = mymap.end();
	for (;ib!=ie;ib++)
	{
		cout << (*ib).first << "   "<<(*ib).second << endl;
	}

	auto pfind = mymap.find("yincheng");
	cout << "\n\n\n";
	cout << (*pfind).first << "   " << (*pfind).second<< endl;
	cout << "\n\n\n";
	auto it = mymap.equal_range("yincheng");//从树节点吧关键字相同的链表全部拔下


	//first起点,,secondl链表最后的节点后面一个空节点,都是迭代器
	for (auto i = it.first; i != it.second;i++)
	{
		cout << (*i).first << "   " << (*i).second << endl;
	}

	cin.get();
	cin.get();
}

Bitset

#include <set>
#include <bitset>
#include <iostream>
#include<string>

using namespace std;

void main3X()
{	
	//8 位, (215)代表构造的数据 
	bitset<8>bs(215);
	for (int i = 0; i < 8;i++)//最高位存储i=7上
	{
		cout << bs[i];
	}

	cin.get();
	cin.get();
}

void main3Y()
{
	//8 位, (215)代表构造的数据 
	bitset<8>bs(215);
	for (int i = 7; i >=0; i--)
	{
		cout << bs[i] << "  " << ~bs[i] << endl;
	}

	cin.get();
	cin.get();
}

void  main3Z()
{
	float num = 1231231236.8;
	bitset<32> myset(num);
	for (int i = 31; i >=0;i--)
	{
		cout << myset[i];
	}

	cin.get();
}

void  main3S()
{
	int  num =-5;
	bitset<32> myset(num);
	for (int i = 31; i >= 0; i--)
	{
		cout << myset[i];
	}
	string str = myset.to_string();
	cout <<"\n" <<str << endl;

	unsigned int data;
	data = myset.to_ulong();//补码
	cout << "\n" << data<< endl;

	cin.get();
}

void main345()
{
	bitset<8>bs(255);
	bs.set(7, 0);//操作二进制位
	bs.set(0, 0);
	cout << bs.size() << endl;//位数
	//bs.reset();//全部清零
	//bs.none();//测试下是否有越位
	for (int i = 7; i >=0; i--)//最高位存储i=7上
	{
		cout << bs[i];
	}

	cin.get();
}

String容器

#include<string>
#include <iostream>
#include <stdlib.h>

using namespace std;
//字符串初始化
void main1s()
{
	char str[124] = "china is  big";
	//str = "12321";C写法

	//string str1(str);
	//str1 = "china  is great";
	string str1("ABCDEFG");
	str1 = "china  is  china";
	std::cout << str1;
	
	cin.get();
}

void main2s()
{
	string str1("ABCD");
	string str2("1234");
	string str3 = str1 + str2;
	std::cout << str3;

	char stra[12]="1231";
	char strb[24]="2132";
	//char strc[36] = stra + strb;
	cin.get();
}

void main3s()
{
	string str1("ABCD");
	string str2("1234");
	str1.append(str2);
	str1 += str2;//字符串的增加
	std::cout << str1;

	cin.get();
}

void main4s()
{
	string str1("ABCD");
	string str2("1234");
	//任意位置插入字符
	str1.insert(str1.begin(),'X');
	str1.insert(str1.end(), 'X');
	str1.insert(str1.begin()+3,3, 'X');

	std::cout << str1;

	cin.get();
}

void  main5s()
{
	string str1("12345678");
	auto ib = str1.begin();
	auto ie = str1.end();
	for (;ib!=ie;ib++)
	{
		cout << *ib << endl;
	}
	//str1.erase(str1.begin());//删除一个字符
	//str1.erase(str1.begin()+3,str1.end()-2);//删除某个字符串
	str1.erase(3, 4);//c从第三个字符开始删除四个字符
	cout << str1 << endl;

	cin.get();
}

void main6s()
{
	string str1("12345678china");
	str1.replace(5, 3, "china");//从0到第三个字符替换为china
	//replace,1位置,长度,字符串
	
	cout << str1 << endl;


	cin.get();
}

void mainA1()
{
	string str("233锄禾日当午,谭胜把地雷买下土,谭胜来跳舞,炸成250");
	//cout << (int)str.find("谭胜大爷") << endl;
	//int pos = str.find(",");//找到第一个皮配的,不匹配返回-1,
	//int pos = str.rfind("谭胜");//找到第一个皮配的,不匹配返回-1,
	//int pos = str.find("谭胜");
	
	cin.get();
}

void mainA2()
{
	string str("ab123mn");
	//int pos = str.find_first_of("123");
	//find_firstof是第一个找到与字符串皮配字符位置
	//int pos = str.find_first_not_of("abc");
	//find_firstof是第一个找到与字符串不皮配字符位置

	//int pos = str.find_last_of("123");
	//find_firstof是最后一个找到与字符串皮配字符位置
	int pos = str.find_last_not_of("123");

	cout << pos << endl;

	cin.get();
}

void main1234()
{
	string str1 = "calc";
	string str2 = "ABC1";
	char strA[5] = "Asd";
	char strB[5] = "Asd";
	cout <<( str1 == str2) << endl;//重载了运算符
	cout << (strA == strB) << endl;//比较地址

	cout << str1.empty()<<endl;////是否为空
	const char *p = str1.c_str();
	system(p);

	cin.get();
}


void main()
{
	//谭胜 是 流氓
	string str("abc is abc  china is china");
	//int pos = str.find('a', 0);//字符也一样
	//std::cout << pos << endl;
	//pos = str.find('a', pos+1);
	//std::cout << pos << endl;
	int pos = str.find("abc", 0);//find从指定位置查找

	std::cout << pos << endl;
    pos = str.find("abc", pos+3);
	std::cout << pos << endl;

	cin.get();
}

算法函数兰不达表达式以及类重载

#include <iostream>
#include <vector>
#include <algorithm>
#include <functional>

using namespace std;

template<class T>  //模板类,实现对于某些容器元素的操作
class add
{
public:
	void operator()( T &t)//重载()运算符,进行操作
	{
		t *= 2;
		std::cout << t<<"\n";
	}
};

void  go(int a)
{
	a *= 2;
	std::cout << a << "\n";
}

void main()
{
	vector<int> myv;
	myv.push_back(10);
	myv.push_back(9);
	myv.push_back(7);
	myv.push_back(9);

	add<int> addA;//省略,
	//for_each(myv.begin(), myv.end(), addA);
	//for_each(myv.begin(), myv.end(), add<int>());
	//for_each(myv.begin(), myv.end(), go);


	auto fun = [](int a, int b){ return a + b; };//Lanmba表达式

	auto funA = [](int a){a *= 2; cout << a << endl; };
	cout << fun(1, 2) << endl;
	for_each(myv.begin(), myv.end(), funA);
	for_each(myv.begin(), myv.end(), [](int a){a *= 2; cout << a << endl; });
	
	cin.get();
}

GPU编程

比特币挖矿,经常使用gpu进行计算。

Helloworld

//win7 无法对gpu进行直接的调试
#include <amp.h>//gpu计算
#include <iostream>

using namespace concurrency;
using namespace std;

void main()
{
	int a[10] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };
	array_view<int> av(10,a);//GPU计算结构,av存储到GPU显存,根据数组初始化


								  //=直接操作AV,(index<1>idx)操作每一个元素
					//extent每一个元素					//restrict (amp) 定位GPU执行
	parallel_for_each(av.extent, [=](index<1>idx) restrict (amp) 
	{

		av[idx] += 123; 
	});

	for (int i = 0; i < 10;i++)
    {	
		std::cout << av[i] << endl;	 

    }

	cin.get();
}

Gpu调试,需要进行如下的设置

【C/C++学院】0829-位容器multimapmutisetString/算法函数兰不达表达式以及类重载/GPU编程

单点测试

#include <iostream>  
#include <amp.h>
#include <WinBase.h>//操作系统的底层文件,测试时间

#define COUNT 100000

float nickName_GPU[COUNT];
float nickName_CPU[COUNT];

double rungpu(int num)		 restrict(amp)//限定了只能在GPU内部执行
{
	double temp = 0;
	for (int i = 0; i < num; i++)
	{
		temp += i;
	}

	return temp;

}
double runcpu(int num)		 restrict(cpu)	 //只能在CPU内部执行
{
	double temp = 0;
	for (int i = 0; i < num; i++)
	{
		temp += i;
	}
	return temp;

}
double runcpugpu(int num)		 restrict(amp, cpu)//并发执行
{
	double temp = 0;
	for (int i = 0; i < num; i++)
	{
		temp += i;
	}
	return temp;

}


int main()
{
	LARGE_INTEGER freq;
	LARGE_INTEGER strt;
	LARGE_INTEGER ed;//统计时间, 可以精确到毫秒
	QueryPerformanceFrequency(&freq);
	QueryPerformanceCounter(&strt);//查询时间

	double dx[1] = { 0.0 };//数据, 一个元素的数组
	double  db = 0.0;

	concurrency::array_view<double> myview(1, dx);//转到gpu进行计算
	parallel_for_each(myview.extent,
		[=](concurrency::index<1> idx) restrict(amp)
	{
		myview[idx] += rungpu(20000000);
	});

	myview.synchronize();//显式等待GPU计算完成并将数据打回内存
	printf("%f\n", dx[0]);

	QueryPerformanceCounter(&ed);//把每一毫秒全到精确的显示出来
	printf("GPU耗时: %d 毫秒\r\n", (ed.QuadPart - strt.QuadPart) * 1000 / freq.QuadPart);
	QueryPerformanceCounter(&strt);

	printf("%f\n", runcpu(20000000));

	QueryPerformanceCounter(&ed);
	printf("CPU耗时: %d 毫秒\r\n", (ed.QuadPart - strt.QuadPart) * 1000 / freq.QuadPart);
	puts("测试结束");
	
	getchar();
	return 0;
}

int mainW(void)//测试并行计算
{
	LARGE_INTEGER freq;
	LARGE_INTEGER strt;
	LARGE_INTEGER ed;
	QueryPerformanceFrequency(&freq);
	QueryPerformanceCounter(&strt);

	concurrency::array_view<float> myView(COUNT, nickName_GPU); //将数据打入显存  ,100000个元素的数组

	concurrency::parallel_for_each(myView.extent, [=](concurrency::index<1> idx) restrict(amp)
	{
		for (int i = 0; i < COUNT/10; i++)
		{
			myView[idx] = (myView[idx] + 0.1f) / 2.3f;
		}
	});


	myView.synchronize();//显式等待GPU计算完成并将数据打回内存  

	QueryPerformanceCounter(&ed);
	printf("GPU耗时: %d 毫秒\r\n", (ed.QuadPart - strt.QuadPart) * 1000 / freq.QuadPart);
	QueryPerformanceCounter(&strt);


	for (int idx = 0; idx < COUNT; idx++)
	{
		for (int i = 0; i < COUNT/10; i++)
		{
			nickName_CPU[idx] = (nickName_CPU[idx] + 0.1f) / 2.3f;
		}
	}
	QueryPerformanceCounter(&ed);
	printf("CPU耗时: %d 毫秒\r\n", (ed.QuadPart - strt.QuadPart) * 1000 / freq.QuadPart);


	for (int idx = 0; idx < COUNT; idx++)
	{
		if (nickName_CPU[idx] != nickName_GPU[idx])
		{
			puts("CPU和GPU的计算结果不相符!");
			getchar();
			return 0;
		}
	}
	puts("测试结束");


	getchar();
	return 0;
}

Cpu的频率快与gpu,适合于单点计算,但是gpu的容器比较多,适合并行计算。

Cpu优势在于单点计算。围绕一个计算器,只计算一个数,计算速度最快。

Gpu优势:并发计算。Gpu加速程序,

【C/C++学院】0829-位容器multimapmutisetString/算法函数兰不达表达式以及类重载/GPU编程

【C/C++学院】0829-位容器multimapmutisetString/算法函数兰不达表达式以及类重载/GPU编程


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