代码：

students=[
    {"sno":101,"sname":"刘晨曦","sgrade":88},
    {"sno":102,"sname":"王雨轩","sgrade":98},
    {"sno":103,"sname":"王祎伟","sgrade":90},
    {"sno":104,"sname":"李威","sgrade":70},
    {"sno":105,"sname":"景少帅","sgrade":99},
    {"sno":106,"sname":"周泽宇","sgrade":96},       
]


students_sort=sorted(students,
                     key=lambda x:x["sgrade"],
                     reverse=True)




print(f"Source list:{students}")
print(f"Sort result:{students_sort}")

　　

 

 

 

效果：

Source list:[{'sno': 101, 'sname': '刘晨曦', 'sgrade': 88}, {'sno': 102, 'sname': '王雨轩', 'sgrade': 98}, {'sno': 103, 'sname': '王祎伟', 'sgrade': 90}, {'sno': 104, 'sname': '李威', 'sgrade': 70}, {'sno': 105, 'sname': '景少帅', 'sgrade': 99}, {'sno': 106, 'sname': '周泽宇', 'sgrade': 96}]
Sort result:[{'sno': 105, 'sname': '景少帅', 'sgrade': 99}, {'sno': 102, 'sname': '王雨轩', 'sgrade': 98}, {'sno': 106, 'sname': '周泽宇', 'sgrade': 96}, {'sno': 103, 'sname': '王祎伟', 'sgrade': 90}, {'sno': 101, 'sname': '刘晨曦', 'sgrade': 88}, {'sno': 104, 'sname': '李威', 'sgrade': 70}]

　　

 

 

总结：

1. 列表里面插入了字典元素，list里面元素用,号隔开，字典元素放在{}里面，里面的元素也是用,号隔开；
2. 列表元素都可以用sorted函数进行排序；
3. key=lambda x:x["grade"]函数，返回列表grade字段作为索引；
4. desc需要用到reverse=True。