c# – 在接口上拦截

我试图创建类似IAuditable接口的东西,它充当Ninject拦截调用的标记.

假设我有以下内容:

public interface IAuditable
{

}

public interface IProcessor
{
    void Process(object o);
}

public class Processor : IProcessor, IAuditable
{
    public void Process(object o)
    {
        Console.WriteLine("Processor called with argument " + o.ToString());
    }
}

使用此设置:

NinjectSettings settings = new NinjectSettings() { LoadExtensions = true };
IKernel kernel = new StandardKernel(settings);
kernel.Bind<IAuditAggregator>().To<AuditAggregator>().InThreadScope();
kernel.Bind<IAuditInterceptor>().To<AuditInterceptor>();

kernel.Bind(x =>
            x.FromThisAssembly()
            .SelectAllClasses()
            .InheritedFrom<IAuditable>()
            .BindToDefaultInterfaces() //I suspect I need something else here
            .Configure(c => c.Intercept().With<IAuditInterceptor>()));
kernel.Bind<IProcessor>().To<Processor>();

每当我尝试kernel.Get< IProcessor>();我得到一个例外,告诉我有多个绑定可用.

如果我删除kernel.Bind< IProcessor>().到< Processor>()然后它按预期工作,但你可能有一个不实现IAuditable的IProcessor.

我是在正确的轨道上吗?

编辑:建议我尝试使用属性:

public class AuditableAttribute : Attribute
{

}
[Auditable]
public class Processor : IProcessor
{

    public void Process(object o)
    {
        Console.WriteLine("Processor called with argument " + o.ToString());
    }
}
//in setup:
kernel.Bind(x =>
            x.FromThisAssembly()
            .SelectAllClasses()
            .WithAttribute<AuditableAttribute>()
            .BindDefaultInterface()
            .Configure(c => c.Intercept().With<IAuditInterceptor>()));

这导致与使用接口相同的重复绑定问题.

解决方法:

您应该能够为实现IAuditable的类型编写一个约定绑定,为未实现的类型编写一个约定绑定.

        kernel.Bind(x =>
            x.FromThisAssembly()
                .SelectAllClasses()
                .InheritedFrom<IAuditable>()
                .BindDefaultInterfaces()
                .Configure(c => c.Intercept().With<IAuditInterceptor>()));

        kernel.Bind(x =>
            x.FromThisAssembly()
                .SelectAllClasses()
                .InheritedFrom<IProcessor>()
                .Where(t => !typeof(IAuditable).IsAssignableFrom(t))
                .BindDefaultInterfaces());
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