jquery和servlet如何传递json?

例 3.6  


<html>
<head>
<script src="jquery.js"></script>
<script type="text/javascript">
    function getP(id) {
        $.getJSON("jqueryservlet36", {
            id : id
        }, function(obj) {
            for ( var p in obj) {
                //Servlet 返回值是{type:'"+type+"',price:'"+price+"'}"这样的JSON对象
                //$("#info").toggle();找id为info的元素
                $("#" + p).html(obj[p]);
                /* document.getElementById(p).innerHTML = obj[p];和下一句一样。          
                 $("#"+p).html(obj[p]);
                 */               
            }
        })
    }
</script>
</head>
<body>
    <table width="340" border="1">
        <tr>
            <td id="1" οnclick="getP('1')">点这1</td>
            <td id="2" οnclick="getP('2')">点这2</td>
        </tr>
    </table>

    <table width="340" border="1">
        <tr>
            <td width="170">参数项</td>
            <td width="170">参数值</td>
        </tr>
        <tr>
            <td>型号</td>
            <td id="type">&nbsp;</td>
        </tr>
        <tr>
            <td>价格</td>
            <td id="price">&nbsp;</td>
        </tr>
    </table>
</body>
</html>

package helloWorld;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;


更多内容请见原文,文章转载自:https://blog.csdn.net/qq_44594371/article/details/103063415

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