方法一：dense_rank()结合group by一起使用

select seller_id
from
(
select seller_id,
dense_rank() over (order by sum(price) desc) r
from Sales
group by seller_id
) a
where r=1;

方法二：all

select seller_id
from Sales
group by seller_id
having sum(price)>=all(
select sum(price)
from Sales
group by seller_id);

这是一个多行子查询；all表示和子查询返回的所有值比较。