有很多种方法可以用来找出哪些SQL语句需要优化，但是很久以来，最简单的方法都是分析保存在V$SQL视图中的缓存的SQL信息。通过V$SQL视图，可以确定具有高消耗时间、CUP和IO读取的SQL语句。

1.查看总消耗时间最多的前10条SQL语句
 select *
from (select v.sql_id,
v.child_number,
v.sql_text,
last_load_time,
v.PARSING_USER_ID,
ROUND(v.ELAPSED_TIME / 1000000 / (CASE
               WHEN (EXECUTIONS = 0 OR NVL(EXECUTIONS, 1 ) = 1) THEN
                1
               ELSE
                EXECUTIONS
             END),
             2) "执行时间'S'",
 v.SQL_FULLTEXT,
v.cpu_time,
v.disk_reads,
rank() over(order by v.elapsed_time desc) elapsed_rank
from v$sql v  ) a
where elapsed_rank <= 100  and   last_load_time > to_char(sysdate - 1/24, 'YYYY-MM-DD/HH:MI:SS')    order by "执行时间'S'" desc

查询最近一小时内最慢的SQL:

select executions, cpu_time/1e6 as cpu_sec, elapsed_time/1e6 as elapsed_sec, round(elapsed_time/sqrt(executions)) as important, v.* 
from v$sql v 
where executions > 10 and last_load_time > to_char(sysdate - 1/24, 'YYYY-MM-DD/HH:MI:SS')  
order by important desc

2.查看CPU消耗时间最多的前10条SQL语句
select *
from (select v.sql_id,
v.child_number,
v.sql_text,
v.elapsed_time,
v.cpu_time,
v.disk_reads,
rank() over(order by v.cpu_time desc) elapsed_rank
from v$sql v) a
where elapsed_rank <= 10;

3.查看消耗磁盘读取最多的前10条SQL语句
select *
from (select v.sql_id,
v.child_number,
v.sql_text,
v.elapsed_time,
v.cpu_time,
v.disk_reads,
rank() over(order by v.disk_reads desc) elapsed_rank
from v$sql v) a
where elapsed_rank <= 10;

 

 

 

  二、查询次数最多的 sql   select *  from(selects.SQL_TEXT,         s.EXECUTIONS"执行次数",         s.PARSING_USER_ID"用户名",         rank() over(orderbyEXECUTIONS desc) EXEC_RANK      fromv$sql s      leftjoinall_users u       onu.USER_ID = s.PARSING_USER_ID) t  whereexec_rank <= 100;     转载：https://www.cnblogs.com/bzdmz/p/11231815.html