在子线程中，写成这样就不提示溢出了

use std::thread;
use std::time::Duration;
fn main() {    
    thread::Builder::new().stack_size(1 * 1024 * 1024 * 1024 * 1024).spawn(spawn_function).unwrap();   
    thread::sleep(Duration::from_millis(5000));   
  }

  fn spawn_function() {
    let _foo:&mut [i8] = &mut [1i8; 1 * 1024 * 1024 * 1024 * 1024 ];
    thread::sleep(Duration::from_millis(5000));   
  }    

 

 

 

 

参考：https://*.com/questions/28914042/thread-main-has-overflowed-its-stack-in-rust

http://www.voidcn.com/article/p-qpgumhtw-btk.html

https://www.runoob.com/rust/rust-concurrency.html

https://blog.csdn.net/weixin_39526185/article/details/111610386