实现目标：
1.ReentrantLock
建立一个容器，10个消费者，2个生产者，消费者消费数据，生产者生产数据。
容器中数据达到10，生产者等待，消费者进行消费
容器中数据为0，消费者等待，生产者进行生产

public class TestContainer<W> {
    List<W> list=Collections.synchronizedList(new ArrayList());
    final static int MAX=10;
    static int count=0;
    Lock lock = new ReentrantLock();
    Condition producer = lock.newCondition();
    Condition consumer = lock.newCondition();
    //producer
    public void put(W w){
        try {
            lock.lock();
            while (list.size()==MAX){
                producer.await();
            }
            list.add(w);
            count++;
            consumer.signalAll();
        } catch (Exception e) {
            e.printStackTrace();
        }finally {
            lock.unlock();
        }
    }
    //consumer
    public W get(){
        W w=null;
        try {
            lock.lock();
            while (list.size()==0){
                consumer.await();
            }
            list.remove(0);
            count--;
            producer.signalAll();
        } catch (Exception e) {
            e.printStackTrace();
        }finally {
            lock.unlock();
        }
        return w;
    }

    public static void main(String[] args) {
        TestContainer<String> c = new TestContainer();
        //10个消费者
        for (int i = 0; i <10 ; i++) {
            new Thread(()->{
                for (int j = 0; j <5 ; j++) {
                    System.out.println(Thread.currentThread().getName()+"---"+j);
                    c.get();
                }
            },"consumer"+i).start();
        }
        try {
            Thread.sleep(1000);
        } catch (Exception e) {
            e.printStackTrace();
        }
        //2个生产者
        for (int i = 0; i <2 ; i++) {
            new Thread(()->{
                for (int j = 0; j <30 ; j++) {
                    System.out.println(Thread.currentThread().getName()+"---"+j);
                    c.put("1111");
                }
            },"producer"+i).start();
        }
    }
}

2.wait()notifyAll实现上述目标
此代码存在问题，生产者wait()，让出锁，有可能生产者再次抢到锁，执行多余代码。
消费者也有此情况。

public class WaitNotifyAll {
    final private LinkedList list = new LinkedList<>();
    Object o=new Object();
    final int MAX=10;
    int count=0;

    public void put(){
        synchronized (this){
            while(list.size()==MAX){
                try {
                    this.wait();
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }
            list.add(o);
            ++count;
            this.notifyAll();
        }
    }
    public void get(){
        synchronized (this){
            while(list.size()==0){
                try {
                    this.wait();
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }
            list.removeFirst();
            count--;
            this.notifyAll();
        }
    }
    public static void main(String[] args) {
        WaitNotifyAll c = new WaitNotifyAll();
        //消费者
        for (int i = 0; i <10 ; i++) {
            new Thread(()->{
                for (int j = 0; j <5 ; j++) {
                    System.out.println(Thread.currentThread().getName()+"----"+j);
                    c.get();
                }
            },"c").start();
        }

        try {
            Thread.sleep(1000);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }

        //生产者
        for (int i = 0; i <2 ; i++) {
            new Thread(()->{
                for (int j = 0; j <30 ; j++) {
                    System.out.println(Thread.currentThread().getName()+"----"+j);
                    c.put();
                }
            },"p").start();
        }
    }
}