iOS通过代码来实现退出应用程序

之前一直没有遇到过需要直接在程序中退出应用程序的情况,今天有这个需求,我在网上查了一下,代码如下

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// 退出当前程序
- (void)exitApplication {
     
    [UIView beginAnimations:@"exitApplication" context:nil];
     
    [UIView setAnimationDuration:0.5];
     
    [UIView setAnimationDelegate:self];
     
    // [UIView setAnimationTransition:UIViewAnimationCurveEaseOut forView:self.view.window cache:NO];
     
    [UIView setAnimationTransition:UIViewAnimationTransitionCurlDown forView:self.view cache:NO];
     
    [UIView setAnimationDidStopSelector:@selector(animationFinished:finished:context:)];
     
    //self.view.window.bounds = CGRectMake(0, 0, 0, 0);
     
    self.view.bounds = CGRectMake(0, 0, 0, 0);
     
    [UIView commitAnimations];
     
}
 
- (void)animationFinished:(NSString *)animationID finished:(NSNumber *)finished context:(void *)context {
     
    if ([animationID compare:@"exitApplication"] == 0) {
         
        exit(0);
         
    }

 其实只需要一句哈就可以了  ,如果嫌麻烦的话可以直接使用

exit(0);

iOS通过代码来实现退出应用程序,布布扣,bubuko.com

iOS通过代码来实现退出应用程序

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