已知空的储钱罐和装了硬币的储钱罐的质量。然后给了n种硬币的质量和价值。
问储钱罐里最少有多少钱。
Sol:完全背包
#include <cstdio> #include <iostream> #include <cstring> #include <algorithm> using namespace std; const int INF = 0x3f3f3f3f; const int maxm = 10000 + 10; const int maxn = 500 + 10; int dp[maxm]; int value[maxn];//每袋的价格 int weight[maxn];//每袋的重量 int nValue,nKind; //完全背包,代价为cost,获得的价值为weight void CompletePack(int cost,int weight) { for(int i=cost;i<=nValue;i++) dp[i]=min(dp[i],dp[i-cost]+weight); } int main() { int T,n,m; scanf("%d",&T); while(T--) { scanf("%d%d",&n,&m); nValue=m-n; scanf("%d",&nKind); for(int i=0;i<nKind;i++) scanf("%d%d",&weight[i],&value[i]); for(int i=0;i<=nValue;i++) dp[i]=INF; dp[0]=0; for(int i=0;i<nKind;i++) CompletePack(value[i],weight[i]); if(dp[nValue]>=INF) printf("This is impossible.\n"); else printf("The minimum amount of money in the piggy-bank is %d.\n",dp[nValue]); } return 0; }