function getUrl(name="") {
var url = location.search; //获取url中"?"符后的字串
var theRequest = new Object();
if (url.indexOf("?") != -1) {
var str = url.substr(1);
strs = str.split("&");
for(var i = 0; i < strs.length; i ++) {
theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]);
}
}
if(name == ""){
return theRequest;
}else{
return theRequest[name]?theRequest[name]:'';
}
}
用法:getUrl("id");
注意
1.不传入值则返回地址的所有参数
2.若没有找到匹配的参数则返回一个空的JSON