B. Obtain Two Zeroes

time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output

You are given two integers aa and bb. You may perform any number of operations on them (possibly zero).

During each operation you should choose any positive integer xx and set a:=a−xa:=a−x, b:=b−2xb:=b−2x or a:=a−2xa:=a−2x, b:=b−xb:=b−x. Note that you may choose different values of xx in different operations.

Is it possible to make aa and bb equal to 00 simultaneously?

Your program should answer tt independent test cases.

Input

The first line contains one integer tt (1≤t≤1001≤t≤100) — the number of test cases.

Then the test cases follow, each test case is represented by one line containing two integers aa and bb for this test case (0≤a,b≤1090≤a,b≤109).

Output

For each test case print the answer to it — YES if it is possible to make aa and bb equal to 00 simultaneously, and NO otherwise.

You may print every letter in any case you want (so, for example, the strings yEs, yes, Yes and YES will all be recognized as positive answer).

Example input Copy

3
6 9
1 1
1 2

output Copy

YES
NO
YES

Note

In the first test case of the example two operations can be used to make both aa and bb equal to zero:

1. choose x=4x=4 and set a:=a−xa:=a−x, b:=b−2xb:=b−2x. Then a=6−4=2a=6−4=2, b=9−8=1b=9−8=1;
2. choose x=1x=1 and set a:=a−2xa:=a−2x, b:=b−xb:=b−x. Then a=2−2=0a=2−2=0, b=1−1=0b=1−1=0.

题解：

 

 CODE:

#include<iostream>
using namespace std;
int m ,n;
int main()
{
    int t;
    cin>>t;
    for(int i=0;i<t;++i)
    {
        cin>>m>>n;
        if(m>n)swap(m,n);
        if((m+n)%3!=0||2*m<n)
        {
            cout<<"NO"<<endl;
        }
        else
        {
            cout<<"YES"<<endl;
        }
    }
    return 0;
 }