我在我的应用程序中使用Spring 3.1 Hibernate 4.1.我想使用Jasypt将某些字段(例如密码)以加密形式存储.但是在集成中,我面临以下异常：

java.lang.AbstractMethodError: org.jasypt.hibernate.type.EncryptedStringType.nullSafeSet(Ljava/sql/PreparedStatement;Ljava/lang/Object;ILorg/hibernate/engine/spi/SessionImplementor;)V

为了将Spring hibernate与Jasypt集成在一起,我遵循以下步骤：

>在lib文件夹中添加了jasypt-1.8.jar.
>在dispatcher-servlet(配置文件)中添加了以下内容

< bean id =“ hibernateStringEncryptor”
        class =“ org.jasypt.hibernate.encryptor.HibernatePBEStringEncryptor”
        lazy-init =“ false”>
        
            hibernateStringEncryptor
        
        
            茉莉花
        
    < / bean>
>在实体上放置以下代码：

@TypeDef(
                name =“ encryptedString”,
                typeClass = EncryptedStringType.class,
                参数= {
                        @Parameter(name =“ encryptorRegisteredName”,value =“ hibernateStringEncryptor”)
                        }
                )

但是它没有得到预期的结果.请帮助我解决此异常.

问候,

阿伦·库玛(Arun Kumar)

解决方法:

根据EncryptedStringType的javadocs：

A Hibernate 3 UserType implementation which allows transparent
encryption of String values during persistence of entities.

并根据Hibernate 4 Migration Guide：

References to org.hibernate.usertype.UserType methods should be changed as indicated:

nullSafeGet(ResultSet rs, String[] names, Object owner) should be changed to
nullSafeGet(ResultSet rs, String[] names, SessionImplementor session, Object owner)
nullSafeSet(PreparedStatement st, Object value, int index) should be changed to
nullSafeSet(PreparedStatement st, Object value, int index, SessionImplementor session)

因此jasypt 1.8与Hibernate 4.x不兼容.

您必须升级到jasypt 1.9,根据this的说法,它提供了Hibernate 4支持.

编辑：

Jasypt documentation提供了一个很好的概述.

第一句话：

Jasypt provides the jasypt-hibernate3 and jasypt-hibernate4 artifacts
for Hibernate integration. Since jasypt 1.9.0, these artifacts must be
added to your classpath separately.

因此,您需要将jasypt-hibernate4.jar添加到您的类路径中以解决编译错误.