DataTable-Add实现

第一步:声明

1             DataTable recordsToShow = new DataTable();
2             recordsToShow.Columns.Add("ResultID", typeof(string));
3             recordsToShow.Columns.Add("Username", typeof(string));
4             recordsToShow.Columns.Add("RealName", typeof(string));
5             recordsToShow.Columns.Add("CompanyName", typeof(string));
6             recordsToShow.Columns.Add("BTime", typeof(string));
7             recordsToShow.Columns.Add("ETime", typeof(string));
8             recordsToShow.Columns.Add("Score", typeof(string));
9             recordsToShow.Columns.Add("IP", typeof(string));

第二步:给DataTable 赋值   

examResults用于循环赋值的数组
 1                 foreach (var result in examResults)
 2                 {
 3                     var row = recordsToShow.NewRow();
 4                     row.SetField("Username", result.Username);
 5                     row.SetField("ResultID", result.Result_ID);
 6                     row.SetField("RealName", NetTrmp.Common.BLL.People.GetPeopleNameByUsername(result.Username));
 7                     row.SetField("CompanyName", NetTrmp.Common.BLL.People.GetCompanyNameByUsername(result.Username, true));
 8                     row.SetField("BTime", result.BTime.HasValue ? result.BTime.Value.ToString("yyyy-MM-dd HH:mm:ss") : string.Empty);
 9                     row.SetField("ETime", result.ETime.HasValue ? result.ETime.Value.ToString("yyyy-MM-dd HH:mm:ss") : string.Empty);
10                     row.SetField("Score", (result.Score * result.Rate).Value.ToString(numberformatstring));
11                     row.SetField("IP", result.IP);21 
22                     recordsToShow.Rows.Add(row);
23                 }

 

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