1、去重复、按add顺序输出、元素排序
package demo02; import org.junit.Test; import java.util.Comparator; import java.util.HashSet; import java.util.LinkedHashSet; import java.util.Objects; import java.util.Set; import java.util.TreeSet; /** * @description: demo01 * @author: liuyang * @create: 2021-09-03 9:36 */ public class Demo01 { @Test public void test1() { /** * 无序不可重复,对象需要重写equals和hashCode方法 * 来确定是否重复的判断逻辑 */ Set<User> set = new HashSet<>(); set.add(new User("AAA", 20)); // 此元素添加失败,根据equals和hashCode方法的结果确定是否重复 set.add(new User("AAA", 20)); System.out.println(set); } @Test public void test2() { /** * LinkedHashSet可按照add元素的顺序遍历输出元素 */ Set<User> set = new LinkedHashSet<>(); set.add(new User("CCC", 18)); set.add(new User("BBB", 30)); set.add(new User("AAA", 16)); // 此元素添加失败,根据equals和hashCode方法的结果确定是否重复 set.add(new User("AAA", 16)); System.out.println(set); } @Test public void test3() { /** * TreeSet只能添加相同类型的元素, * 可自动将元素进行自然排序(前提是元素需要实现Comparable接口) */ Set<String> set = new TreeSet<>(); set.add("CCC"); set.add("BBB"); set.add("AAA"); System.out.println(set); // [AAA, BBB, CCC] // 自然排序需实现Comparable接口重写compareTo方法 Set<User> set1 = new TreeSet<>(); set1.add(new User("CCC", 18)); set1.add(new User("BBB", 30)); set1.add(new User("AAA", 16)); // 注意此时这个元素添加失败,因为此时不可重复取决于compareTo方法的结果 set1.add(new User("AAA", 19)); System.out.println(set1); // 定制排序,TreeSet构造器中传入Comparator接口的实例对象 Set<User> set2 = new TreeSet<>(new Comparator<User>() { @Override public int compare(User o1, User o2) { return o1.getName().compareTo(o2.getName()); } }); set2.add(new User("CCC", 18)); set2.add(new User("BBB", 30)); set2.add(new User("AAA", 19)); // 注意此时这个元素添加失败,因为此时不可重复取决于compare方法的结果 set2.add(new User("AAA", 16)); System.out.println(set2); } } class User implements Comparable<User> { private String name; private int age; public User(String name, int age) { this.name = name; this.age = age; } public String getName() { return name; } public void setName(String name) { this.name = name; } public int getAge() { return age; } public void setAge(int age) { this.age = age; } @Override public boolean equals(Object o) { if (this == o) return true; if (o == null || getClass() != o.getClass()) return false; User user = (User) o; return age == user.age && Objects.equals(name, user.name); } @Override public int hashCode() { return Objects.hash(name, age); } @Override public String toString() { return "User{" + "name=‘" + name + ‘\‘‘ + ", age=" + age + ‘}‘; } @Override public int compareTo(User o) { return this.name.compareTo(o.name); } }