2019 ICPC Asia Taipei Hsinchu Regional

A. Rush Hour Puzzle

B. The Power Monitor System

C. Are They All Integers?

2019 ICPC Asia Taipei Hsinchu Regional
#include <bits/stdc++.h>
using namespace std;
int n, a[110];
int main()
{
    scanf("%d", &n);
    for (int i = 0; i < n; i++)
        scanf("%d", &a[i]);
    for (int i = 0; i < n; i++)
        for (int j = 0; j < n; j++)
            for (int k = 0; k < n; k++)
                if (i != j && i != k && j != k && abs(a[i] - a[j]) % a[k])
                    return printf("no"), 0;
    printf("yes");
    return 0;
}
View Code

D. Tapioka

2019 ICPC Asia Taipei Hsinchu Regional
#include <bits/stdc++.h>
using namespace std;
bool f;
int main()
{
    string s;
    while (cin >> s)
    {
        if (s != "bubble" && s != "tapioka")
            cout << s << " ", f = 1;
    }
    if (!f) cout << "nothing";
    return 0;
}
View Code

E. The League of Sequence Designers

2019 ICPC Asia Taipei Hsinchu Regional
#include <bits/stdc++.h>
using namespace std;
int main()
{
    int cass, k, l;
    for (cin >> cass; cass; cass--)
    {
        cin >> k >> l;
        if (l >= 2000)
        {
            puts("-1");
            continue;
        }
        cout << 1999 << endl << -1 << " ";
        for (int i = 2; i <= 1998; i++)
            cout << 1 + (k / 1997) << " ";
        cout << 2 + (k - (k / 1997) * 1997) << endl;
    }
    return 0;
}
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F. Miss Sloane

G. Optimal Selection

H. Mining a

2019 ICPC Asia Taipei Hsinchu Regional
#include <bits/stdc++.h>
#define ll long long
using namespace std;
int main()
{
    ll n, cass;
    for (cin >> cass; cass; cass--)
    {
        cin >> n;
        cout << ((n * (n + 1)) ^ (n + 1)) << endl;
    }
    return 0;
}
View Code

I. The Spectrum

J. Automatic Control Machine

2019 ICPC Asia Taipei Hsinchu Regional
#include <bits/stdc++.h>
using namespace std;
bitset<510> num[30];
char s[1010];
int main()
{
    int cass;
    for (scanf("%d", &cass); cass; cass--)
    {
        int n, m;
        scanf("%d%d", &n, &m);
        for (int i = 0; i < m; i++)
        {
            scanf("%s", s);
            num[i] = bitset<510>(s);
        }
        int len = 1 << m, ans = m + 1;
        for (int i = 1; i < len; i++)
        {
            int t = i, cnt = 0;
            bitset<510> now(0);
            for (int j = 0; j < m && t; j++, t >>= 1)
                if (t & 1) now = now | num[j], cnt++;
            if (now.count() == n) ans = min(ans, cnt);
        }
        printf("%d\n", ans == m + 1 ? -1 : ans);
    }
    return 0;
}
View Code

K. Length of Bundle Rope

2019 ICPC Asia Taipei Hsinchu Regional
#include <bits/stdc++.h>
using namespace std;
priority_queue<int, vector<int>, greater<int> > q;
int main()
{
    int n, cass;
    for (scanf("%d", &cass); cass; cass--)
    {
        while (!q.empty()) q.pop();
        scanf("%d", &n);
        for (int i = 0, x; i < n; i++)
            scanf("%d", &x), q.push(x);
        int ans = 0;
        while (q.size() > 1)
        {
            int x = q.top();
            q.pop();
            x += q.top();
            q.pop();
            ans += x, q.push(x);
        }
        printf("%d\n", ans);
    }
    return 0;
}
View Code

L. Largest Quadrilateral

M. DivModulo

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