一 问题
自己开发的程序，如何用shell 脚本实现 启动，关闭，重启，查看状态？
二 方案
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#!/bin/sh
SERVICE="my_service"
start(){
echo "starting..."
nohup $SERVICE > $SERVICE.log 2>&1 &
if [ $? -ne 0 ]
then
echo "start failed, please check the log!"
exit $?
else
echo $! > $SERVICE.pid
echo "start success"
fi
}
stop(){
echo "stopping..."
kill -9 `cat $SERVICE.pid`
if [ $? -ne 0 ]
then
echo "stop failed, may be $SERVICE isn't running"
exit $?
else
rm -rf $SERVICE.pid
echo "stop success"
fi
}
restart(){
stop&&start
}
status(){
num=`ps -ef | grep $SERVICE | grep -v grep | wc -l`
if [ $num -eq 0 ]
then
echo "$SERVICE isn't running"
else
echo "$SERVICE is running"
fi
}
case $1 in start) start ;;
stop) stop ;;
restart) restart ;;
status) status ;;
*) echo "Usage: $0 {start|stop|restart|status}" ;;
esac exit 0
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本文转自 boy461205160 51CTO博客，原文链接:http://blog.51cto.com/461205160/1740578