package com.array; public class ArrayDemo06 { //稀疏数组 public static void main(String[] args) { //1.创建一个11*11的二维数组 0:无棋子 1:黑棋 2:白棋 int[][] array1=new int[11][11]; array1[1][2]=1; array1[2][3]=2; System.out.println("输出原始数组:"); for (int[] ints : array1) { for (int anInt : ints) { System.out.print(anInt+"\t"); } System.out.println(); } //转化为稀疏数组保存 //获取有效值的个数 int sum=0; for (int[] ints : array1) { for (int anInt : ints) { if(anInt!=0)sum++; } } System.out.println("有效值的个数为:"+sum); //输出2 System.out.println("==============================="); //2.创建一个稀疏数组 int[][] array2=new int[sum+1][3]; array2[0][0]=11; array2[0][1]=11; array2[0][2]=sum; //遍历二维数组,将非零的值存放在稀疏数组中 int count=0; for (int i = 0; i < array1.length; i++) { for (int j = 0; j < array1[i].length; j++) { if(array1[i][j]!=0){ count++; array2[count][0]=i; array2[count][1]=j; array2[count][2]=array1[i][j]; } } } for (int[] ints : array2) { for (int anInt : ints) { System.out.print(anInt+"\t"); } System.out.println(); } System.out.println("==============================="); //3.读取稀疏数组(还原) int[][] array3=new int[array2[0][0]][array2[0][1]]; for (int i = 1; i < array2.length; i++) { array3[array2[i][0]][array2[i][1]]=array2[i][2]; } System.out.println("输出还原的数组:"); for (int[] ints : array3) { for (int anInt : ints) { System.out.print(anInt+"\t"); } System.out.println(); } } }
输出结果:
输出原始数组: 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 有效值的个数为:2 =============================== 11 11 2 1 2 1 2 3 2 =============================== 输出还原的数组: 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 Process finished with exit code 0