def calnumber(a,k):#a为列表，k为查找数字
    count=0
    for i in a:
        if i == k:
            count = count + 1
        else:
            continue
    return count
a=[1,2,3,4,1,3]
length=calnumber(a,1)
print(length)

a=[1,2,3,4,1,3]

print set(a)

a = [1,2,2,2,8,3,3,4,5,4,4]
b = set(a)
for item in b:
  print("the %d has found %d Times" %(item,a.count(item)))

a = [1,2,2,2,8,3,3,4,5,4,4]
b = set(a)
newlist=[]
for item in b:
    length=0
    length=a.count(item)
    newlist=newlist+addnum_toList(length, item)
print(newlist)

a=[1,2,3,1,2]
b=[1,2,3,1,2]
c=[1,2,3]
print(operator.eq(a,b))#判断两个list是否相等
print(operator.eq(a,c))