Zhejiang University has 40,000 students and provides 2,500 courses. Now given the registered course list of each student, you are supposed to output the student name lists of all the courses.

Input Specification:

Each input file contains one test case. For each case, the first line contains 2 numbers: N (≤40,000), the total number of students, and K (≤2,500), the total number of courses. Then N lines follow, each contains a student’s name (3 capital English letters plus a one-digit number), a positive number C (≤20) which is the number of courses that this student has registered, and then followed by C course numbers. For the sake of simplicity, the courses are numbered from 1 to K.

Output Specification:

For each test case, print the student name lists of all the courses in increasing order of the course numbers. For each course, first print in one line the course number and the number of registered students, separated by a space. Then output the students’ names in alphabetical order. Each name occupies a line.

Sample Input:

10 5
ZOE1 2 4 5
ANN0 3 5 2 1
BOB5 5 3 4 2 1 5
JOE4 1 2
JAY9 4 1 2 5 4
FRA8 3 4 2 5
DON2 2 4 5
AMY7 1 5
KAT3 3 5 4 2
LOR6 4 2 4 1 5

Sample Output:

1 4
ANN0
BOB5
JAY9
LOR6
2 7
ANN0
BOB5
FRA8
JAY9
JOE4
KAT3
LOR6
3 1
BOB5
4 7
BOB5
DON2
FRA8
JAY9
KAT3
LOR6
ZOE1
5 9
AMY7
ANN0
BOB5
DON2
FRA8
JAY9
KAT3
LOR6
ZOE1

解释：

输入学生总数N，在输入课程总数K

接下来N行输入每个学生的选课信息包括，学生姓名，课程总数，各个课程编号

输出：

按课程编程从1-K输出

先输出课程编号，然后是课程人数

接下数额该课程的学生名称，按照字典升序

#include<stdio.h>
#include<vector>
#include<string.h>
#include<iostream>
#include<algorithm>
const int Max=2510;
using namespace std;
char name[41000][5];    //存放学生姓名
vector <int> Class[Max];//Class[i]存放第门课所有学生姓名在数组中的编号
bool cmp(int a,int b){
    return strcmp(name[a],name[b])<0;//名字按字典序升序
}
int main()
{
    int N,M,k,courseid;
    //输入总学生数，和总课程数
    cin>>N>>M;
    for(int i=0;i<N;i++)
    {
        //输入学生姓名和课程数
        cin>>name[i]>>k;
        //输入课程编号
        for(int j=0;j<k;j++){
            cin>>courseid;
            Class[courseid].push_back(i);
        }
    }
	//输出结果
    for(int i=1;i<=M;i++)
    {
        //输出课程编号，课程人数
        cout<<i<<" "<<Class[i].size()<<endl;
        //名字排序完输出
        sort(Class[i].begin(),Class[i].end(),cmp);
        for(int j=0;j<Class[i].size();j++)
            printf("%s\n",name[Class[i][j]]);
    }
    return 0;
}