【leetcode】1646. Get Maximum in Generated Array

题目如下:

You are given an integer n. A 0-indexed integer array nums of length n + 1 is generated in the following way:

  • nums[0] = 0
  • nums[1] = 1
  • nums[2 * i] = nums[i] when 2 <= 2 * i <= n
  • nums[2 * i + 1] = nums[i] + nums[i + 1] when 2 <= 2 * i + 1 <= n

Return the maximum integer in the array nums​​​.

 

Example 1:

Input: n = 7
Output: 3
Explanation: According to the given rules:
  nums[0] = 0
  nums[1] = 1
  nums[(1 * 2) = 2] = nums[1] = 1
  nums[(1 * 2) + 1 = 3] = nums[1] + nums[2] = 1 + 1 = 2
  nums[(2 * 2) = 4] = nums[2] = 1
  nums[(2 * 2) + 1 = 5] = nums[2] + nums[3] = 1 + 2 = 3
  nums[(3 * 2) = 6] = nums[3] = 2
  nums[(3 * 2) + 1 = 7] = nums[3] + nums[4] = 2 + 1 = 3
Hence, nums = [0,1,1,2,1,3,2,3], and the maximum is max(0,1,1,2,1,3,2,3) = 3.

Example 2:

Input: n = 2
Output: 1
Explanation: According to the given rules, nums = [0,1,1]. The maximum is max(0,1,1) = 1.

Example 3:

Input: n = 3
Output: 2
Explanation: According to the given rules, nums = [0,1,1,2]. The maximum is max(0,1,1,2) = 2.

Constraints:

  • 0 <= n <= 100

解题思路:反正n最大才100,挨个算吧。

代码如下:

class Solution(object):
    def getMaximumGenerated(self, n):
        """
        :type n: int
        :rtype: int
        """
        if n == 0:return 0
        val = [0,1] + [0] * (n-1)
        for i in range(2,n+1):
            if i % 2 == 0:
                val[i] = val[i/2]
            else:
                val[i] = val[i/2] + val[i/2+1]
        return max(val)

 

上一篇:c++PTAA1007(dp累加)


下一篇:1007 Maximum Subsequence Sum