UVa 621 Secret Research

  Secret Research 

At a certain laboratory results of secret research are thoroughly encrypted. A result of a single experiment is stored as an information of its completion:

 


`positive result‘, `negative result‘, `experiment failed‘ or `experiment not completed‘

 


The encrypted result constitutes a string of digits S, which may take one of the following forms:

 


UVa 621 Secret Research
positive result 		 S = 1 or S = 4 or S = 78 
UVa 621 Secret Research
negative result 		 S = S35 
UVa 621 Secret Research
experiment failed 		 S = 9S4 
UVa 621 Secret Research
experiment not completed 		 S = 190S

(A sample result S35 means that if we add digits 35 from the right hand side to a digit sequence then we shall get the digit sequence corresponding to a failed experiment)

 


You are to write a program which decrypts given sequences of digits.

 

Input 

A integer n stating the number of encrypted results and then consecutive n lines, each containing a sequence of digits given as ASCII strings.

 

Output 

For each analysed sequence of digits the following lines should be sent to output (in separate lines):

 


		 + 		  for a positive result
		 - 		  for a negative result
		 * 		  for a failed experiment
		 ? 		  for a not completed experiment

In case the analysed string does not determine the experiment result, a first match from the above list should be outputted.

 

Sample Input 

 

4
78
7835
19078
944

 

Sample Output 

+
-
?
*

 

 


Miguel A. Revilla 
2000-01-10

 

给一个由数字组成的字符串,判断它是题目中描述的哪中格式的,输出相应的符号即可,特别简单几分钟切掉

 

UVa 621 Secret Research
 1 #include<iostream>
 2 #include<cstdio>
 3 #include<cstring>
 4 
 5 using namespace std;
 6 
 7 int main()
 8 {
 9     int n;
10     char s[10000];
11 
12     scanf("%d",&n);
13     getchar();
14 
15     while(n--)
16     {
17         gets(s);
18         int len=strlen(s);
19         if( ( len==1 && (s[0]==1||s[0]==4) ) || ( len==2 && s[0]==7 &&s[1]==8 ) )
20             printf("+\n");
21         else if( len>=3 && s[len-1]==5 && s[len-2]==3 )
22             printf("-\n");
23         else if( len>=3 && s[0]==9 && s[len-1]==4 )
24             printf("*\n");
25         else if( len>=4 && s[0]==1 && s[1]==9 && s[2]==0 )
26             printf("?\n");
27     }
28 
29     return 0;
30 }
[C++]

UVa 621 Secret Research

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