2017/11/9 Leetcode 日记
566. Reshape the Matrix
In MATLAB, there is a very useful function called 'reshape', which can reshape a matrix into a new one with different size but keep its original data.
You're given a matrix represented by a two-dimensional array, and two positive integers r and c representing the row number and column number of the wanted reshaped matrix, respectively.
The reshaped matrix need to be filled with all the elements of the original matrix in the same row-traversing order as they were.
If the 'reshape' operation with given parameters is possible and legal, output the new reshaped matrix; Otherwise, output the original matrix.
(给一个矩阵和r, c，将这个矩阵重新排列成r行c列的矩阵，如果不可能则输出原矩阵。)
class Solution {
public:
vector<vector<int>> matrixReshape(vector<vector<int>>& nums, int r, int c) {
int row = nums.size(), col = nums[].size();
if(row * col != r * c){
return nums;
}
vector<vector<int>> num(r, vector<int>(c, ));
for(int i = ; i < row * col; i++){
num[i/c][i%c] = nums[i/col][i%col];
}
return num;
}
};
c++
class Solution:
def matrixReshape(self, nums, r, c):
"""
:type nums: List[List[int]]
:type r: int
:type c: int
:rtype: List[List[int]]
"""
row, col = len(nums), len(nums[])
if row * col != r * c:
return nums
o = r*c num = [[None] * c for _ in range(r)]
for i in range(, o):
num[i//c][i%c] = nums[i//col][i%col] return num
python3
682. Baseball Game
You're now a baseball game point recorder.
Given a list of strings, each string can be one of the 4 following types:
-
Integer(one round's score): Directly represents the number of points you get in this round. -
"+"(one round's score): Represents that the points you get in this round are the sum of the last twovalidround's points. -
"D"(one round's score): Represents that the points you get in this round are the doubled data of the lastvalidround's points. -
"C"(an operation, which isn't a round's score): Represents the lastvalidround's points you get were invalid and should be removed.
Each round's operation is permanent and could have an impact on the round before and the round after.
You need to return the sum of the points you could get in all the rounds.
class Solution {
public:
int calPoints(vector<string>& ops) {
int len = ops.size();
int sum = , index = ;
vector<int> op;
for(int i = ; i < len; i++){
if (ops[i] == "+"){
op.push_back(op[index-] + op[index-]);
}else if (ops[i] == "C"){
op.pop_back();
}else if (ops[i] == "D"){
op.push_back( * op[index-]);
}else{
op.push_back(getNum(ops[i]));
}
index = op.size();
}
return getSum(op);
}
int getNum(string n){
int num = ;
if(n[] == '-'){
for(int i = , sz = n.size(); i<sz; i++){
num *= ;
num += n[i]-'';
}
num = -num;
}else{
for(int i = , sz = n.size(); i<sz; i++){
num *= ;
num += n[i]-'';
}
}
return num;
}
int getSum(vector<int> op){
int sum = ;
for(int i = , sz = op.size(); i<sz; i++){
sum += op[i];
}
return sum;
}
};
c++
class Solution:
def calPoints(self, ops):
"""
:type ops: List[str]
:rtype: int
"""
OP = []
index =
for op in ops:
if op == '+':
OP.append(OP[index-]+OP[index-])
elif op == 'D':
OP.append(*OP[index-])
elif op == 'C':
OP.pop()
else:
OP.append(int(op))
sum =
for o in OP:
sum += o
return sum
Python3