最小割+输出方案
#include<cstdio>
#include<cstring>
#include<string>
#include<cmath>
#include<vector>
#include<queue>
#include<algorithm>
using namespace std; const int maxn=+;
const int INF=0x7FFFFFFF; struct Edge
{
int from,to,cap,flow;
};
vector<Edge>edges;
vector<int>G[maxn];
vector<int>CG[maxn];
bool vis[maxn];
int d[maxn];
int cur[maxn];
int n,m,s,t;
Edge P[maxn]; //求出层次网络
bool BFS()
{
memset(vis,,sizeof(vis));
queue<int>Q;
Q.push(s);
d[s]=;
vis[s]=;
while(!Q.empty())
{
int x=Q.front();
Q.pop();
for(int i=; i<G[x].size(); i++)
{
Edge& e=edges[G[x][i]];
if(!vis[e.to]&&e.cap>e.flow)
{
vis[e.to]=;
d[e.to]=d[x]+;
Q.push(e.to);
}
}
}
return vis[t];
} //加边
void AddEdge(int from,int to,int cap)
{
Edge r;
r.from=from;
r.to=to;
r.cap=cap;
r.flow=;
edges.push_back(r);
Edge d;
d.from=to;
d.to=from;
d.cap=;
d.flow=;
edges.push_back(d);
m=edges.size();
G[from].push_back(m-);
G[to].push_back(m-);
} //每个阶段来一次DFS增广
int DFS(int x,int a)
{
if(x==t||a==) return a;
int flow=,f;
for(int i=cur[x]; i<G[x].size(); i++)
{
Edge& e=edges[G[x][i]];
if(d[x]+==d[e.to]&&(f=DFS(e.to,min(a,e.cap-e.flow)))>)
{
e.flow+=f;
edges[G[x][i]^].flow-=f;
flow+=f;
a-=f;
if(a==) break;
}
}
return flow;
} //多个阶段,多次建立层次网络。
int Maxflow(int ss,int tt)
{
int flow=;
while(BFS())
{
memset(cur,,sizeof(cur));
flow+=DFS(ss,INF);
}
return flow;
} int N,M,Cost;
int U[maxn],V[maxn];
int FF[maxn]; void dfs(int x)
{
FF[x]=;
for(int i=; i<CG[x].size(); i++)
if(!FF[CG[x][i]])
dfs(CG[x][i]);
} int main()
{
while(~scanf("%d%d",&N,&M))
{
if(!N&&!M) break;
edges.clear();
for(int i=; i<maxn; i++) G[i].clear();
for(int i=; i<maxn; i++) CG[i].clear();
memset(FF,,sizeof FF);
s=;
t=;
for(int i=; i<=M; i++)
{
scanf("%d%d%d",&U[i],&V[i],&Cost);
AddEdge(U[i],V[i],Cost);
AddEdge(V[i],U[i],Cost);
}
Maxflow(s,t);
int Tot=;
for(int i=; i<edges.size(); i=i+)
{
P[Tot].from=edges[i].from;
P[Tot].to=edges[i].to;
P[Tot].cap=edges[i].cap;
P[Tot].flow=edges[i].flow;
Tot++;
}
for(int i=; i<Tot; i++)
{
if(P[i].cap-P[i].flow>)
CG[P[i].from].push_back(P[i].to);
if(P[i].flow>)
CG[P[i].to].push_back(P[i].from);
}
dfs(s);
for(int i=; i<=M; i++)
if((FF[U[i]]==&&FF[V[i]]==)||(FF[V[i]]==&&FF[U[i]]==))
printf("%d %d\n",U[i],V[i]);
printf("\n");
}
return ;
}