LightOj1388 - Trapezium Drawing(求梯形点的坐标)

题目链接:http://lightoj.com/volume_showproblem.php?problem=1388

题意:已知梯形的点A B的坐标,以及b c d的长度,求C D两点的坐标;默认AB是梯形平行边的较长边;

LightOj1388 - Trapezium Drawing(求梯形点的坐标)

注意D点可能在A点的左边,AB可能不是水平的,剩下的求根据A点求D点,在根据D点求C点;

#include<stdio.h>
#include<iostream>
#include<string.h>
#include<algorithm>
#include<cmath>
#include<vector>
#include<queue>
#include<set>
using namespace std;
#define met(a, b) memset(a, b, sizeof(a))
#define maxn 10005
#define maxm 20005
#define INF 0x3f3f3f3f
typedef long long LL; int main()
{
int T, tcase = ;
scanf("%d", &T);
while(T --)
{
double b, c, d, ax, ay, bx, by; scanf("%lf %lf %lf %lf %lf %lf %lf", &ax, &ay, &bx, &by, &b, &c, &d); double a = sqrt((ax-bx)*(ax-bx) + (ay-by)*(ay-by));///直线AB的距离; double sina = (by-ay) / a;
double cosa = (bx-ax) / a;
///AB与水平线的sin和cos值; double p = (b+d+a-c)/;
double s = sqrt(p*(p-b)*(p-d)*(p-(a-c)));
double h = s*/(a-c);///D到AB的距离; int flag = ; if(b*b > d*d + (a-c)*(a-c)) flag = ;///角DAB为钝角; double t = sqrt(fabs(d*d - h*h)); if(flag) t = -t; double dx = ax + (t*cosa - h*sina);
double dy = ay + (h*cosa + t*sina); double cx = dx + c*cosa;
double cy = dy + c*sina; printf("Case %d:\n%.8lf %.8lf %.8lf %.8lf\n", tcase++, cx, cy, dx, dy);
}
return ;
}
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