http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=2533
11538 - Chess Queen Time limit: 2.000 seconds |
You probably know how the game of chess is played and how chess queen operates. Two chess queens are in attacking position when they are on same row, column or diagonal of a chess board. Suppose two such chess queens (one black and the other white) are placed on (2 × 2) chess board. They can be in attacking positions in 12 ways, these are shown in the picture below:
Figure: in a (2 × 2) chessboard 2 queens can be in attacking position in 12 ways Given an (N × M) board you will have to decide in how many ways 2 queens can be in attacking position in that.
Input
Input file can contain up to 5000 lines of inputs. Each line contains two non-negative integers which denote the value of M and N (0 < M, N ≤ 106 ) respectively. Input is terminated by a line containing two zeroes. These two zeroes need not be processed.
Output
For each line of input produce one line of output. This line contains an integer which denotes in how many ways two queens can be in attacking position in an (M × N) board, where the values of M and N came from the input. All output values will fit in 64-bit signed integer.
Sample Input
2 2
100 223
2300 1000
0 0
Sample Output
12
10907100
11514134000
分析;
公式: n*m*(m+n-2)+2*n*(n-1)*(3*m-n-1)/3 。
AC代码:
// UVa11538 Chess Queen #include<iostream> #include<algorithm> using namespace std; int main() { unsigned long long n, m; // 最大可以保存2^64-1>1.8*10^19 while(cin >> n >> m) { if(!n && !m) break; if(n > m) swap(n, m); // 这样就避免了对n<=m和n>m两种情况分类讨论 cout << n*m*(m+n-)+*n*(n-)*(*m-n-)/ << endl; } return ; }
吐槽一下:uva 上面看不了自己的代码,只能自己把每个代码都保存下来咯,,,Orz