给定一个二叉树，检查它是否是镜像对称的。

来源：力扣（LeetCode）
链接：https://leetcode-cn.com/problems/symmetric-tree
著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。

递归

class Solution {


    private boolean solve(TreeNode left, TreeNode right) {
        if (left == null && right == null) {
            return true;
        }

        if (left == null || right == null) {
            return false;
        }

        if (left.val != right.val) {
            return false;
        }

        return solve(left.left, right.right) && solve(left.right, right.left);
    }

    public boolean isSymmetric(TreeNode root) {
        if (root == null) {
            return true;
        }
        return solve(root.left, root.right);
    }
}

class TreeNode {
    int val;
    TreeNode left;
    TreeNode right;

    TreeNode() {
    }

    TreeNode(int val) {
        this.val = val;
    }

    TreeNode(int val, TreeNode left, TreeNode right) {
        this.val = val;
        this.left = left;
        this.right = right;
    }
}

迭代

import java.util.LinkedList;
import java.util.Queue;

class Solution {

    public boolean isSymmetric(TreeNode root) {
        if (root == null) {
            return true;
        }

        Queue<TreeNode> queue = new LinkedList<>();
        queue.offer(root.left);
        queue.offer(root.right);

        while (!queue.isEmpty()) {
            TreeNode left = queue.poll();
            TreeNode right = queue.poll();

            if (left == null && right == null) {
                continue;
            }

            if (left == null || right == null) {
                return false;
            }

            if (left.val != right.val) {
                return false;
            }

            queue.offer(left.left);
            queue.offer(right.right);

            queue.offer(left.right);
            queue.offer(right.left);
        }

        return true;
    }
}

class TreeNode {
    int val;
    TreeNode left;
    TreeNode right;

    TreeNode() {
    }

    TreeNode(int val) {
        this.val = val;
    }

    TreeNode(int val, TreeNode left, TreeNode right) {
        this.val = val;
        this.left = left;
        this.right = right;
    }
}