1.基本需求
编写一个查询员工信息表的程序,实现如下功能:
(1)让用户输入不小于3个字符查询员工信息
(2)通过员工号或员工个人信息可以精确或模糊查询到员工信息
(3)输出员工信息
2.实现代码与注释
首先提供员工信息的txt文件:
1
2
3
4
|
xpleaf@xpleaf-machine:/mnt/hgfs/Python/day3$ more student_info.txt stu1101 mingjia.xu 275896019 @qq.com 263 SystemAdmin 18810404260
stu1102 Yangjiansong jason@s156.com A8music SystemAdmin 13601247960
stu1103 zouxinkai zouxinkai_2006@ 126 .com jishubu systemadmin 1861214111
|
基于上述需求,利用列表、字典和元组的相关处理函数,编写如下程序:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
|
#!/usr/bin/env python staff_dic = {} #从文件中读取员工信息,并作为字典处理 f = file( 'student_info.txt' )
for line in f.xreadlines():
stu_id, stu_name, mail, company, title, phone = line.split() #取文件一行中每一列元素
staff_dic[stu_id] = [stu_name, mail, company, title, phone] #key值对应的Value值为一列表
while True:
query = raw_input( '\033[32;1mPlease input the query string:\033[0m' ).strip()
if len(query) < 3 : #如果输入查询的字符少于 3 ,则要求重新输入
print 'You have to input at least 3 letters to query!'
continue
match_counter = 0 #计数器,判断是否有匹配到员工信息
for k,v in staff_dic.items(): #.items(),key值作为列表中,元组的左元素,key值(这里为列表)则作为右元素
index = k.find(query) #find()返回查询到字符串的首个字符的索引,找空串返回 0 ,找不到返回- 1
if k.find(query) != - 1 : #如果找到
print k[:index] + '\033[32;1m%s\033[0m' % query + k[index + len(query):],v #这里会有用户输入的内容进行颜色加深
match_counter += 1
else :
str_v = '\t' .join(v) #将列表中的元素连接为字符串
index = str_v.find(query) #方法如上面查找key值一样
if index != - 1 :
print k,str_v[:index] + '\033[32;1m%s\033[0m' % query + str_v[index + len(query):]
match_counter += 1
print 'Matched \033[31;1m%s\033[0m records!' % (match_counter)
|
3.测试
基于上述的情况,对可能出现的情况和结果,测试如下:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
|
Please input the query string:stu1101 ===>对员工号(键值)精确查询 stu1101 [ 'mingjia.xu' , '275896019@qq.com' , '263' , 'SystemAdmin' , '18810404260' ]
Matched 1 records!
Please input the query string:stu ===>对员工号(键值)模糊查询 stu1103 [ 'zouxinkai' , 'zouxinkai_2006@126.com' , 'jishubu' , 'systemadmin' , '1861214111' ]
stu1102 [ 'Yangjiansong' , 'jason@s156.com' , 'A8music' , 'SystemAdmin' , '13601247960' ]
stu1101 [ 'mingjia.xu' , '275896019@qq.com' , '263' , 'SystemAdmin' , '18810404260' ]
Matched 3 records!
Please input the query string:kai ===>对员工信息(value值)模糊查询 stu1103 zouxinkai zouxinkai_2006@ 126 .com jishubu systemadmin 1861214111
Matched 1 records!
Please input the query string:zou stu1103 zouxinkai zouxinkai_2006@ 126 .com jishubu systemadmin 1861214111
Matched 1 records!
|