1094 The Largest Generation (25 分)

A family hierarchy is usually presented by a pedigree tree where all the nodes on the same level belong to the same generation. Your task is to find the generation with the largest population.

Input Specification:

Each input file contains one test case. Each case starts with two positive integers N (<) which is the total number of family members in the tree (and hence assume that all the members are numbered from 01 to N), and M (<) which is the number of family members who have children. Then M lines follow, each contains the information of a family member in the following format:

ID K ID[1] ID[2] ... ID[K]
 

where ID is a two-digit number representing a family member, K (>) is the number of his/her children, followed by a sequence of two-digit ID's of his/her children. For the sake of simplicity, let us fix the root ID to be 01. All the numbers in a line are separated by a space.

Output Specification:

For each test case, print in one line the largest population number and the level of the corresponding generation. It is assumed that such a generation is unique, and the root level is defined to be 1.

Sample Input:

23 13
21 1 23
01 4 03 02 04 05
03 3 06 07 08
06 2 12 13
13 1 21
08 2 15 16
02 2 09 10
11 2 19 20
17 1 22
05 1 11
07 1 14
09 1 17
10 1 18
 

Sample Output:

9 4


#include<bits/stdc++.h>
using namespace std;
const int maxn=1010;
#define  inf  0x3fffffff
//vector<vector<int> > v;//此方式不能使用,因为存在某没有子节点的结点,但是v数组一位下标不存在
vector<int > v[100];
int num[maxn];
void dfs(int index,int depth){
    num[depth]++;
    for(int i=0;i<v[index].size();i++){
        dfs(v[index][i],depth+1);
    }
}
int main(){
    fill(num,num+maxn,0);
    int n, m, a, k, c;
    scanf("%d %d", &n, &m);
//    v.resize(n);
    for(int i = 0; i < m; i++) {
        scanf("%d %d",&a, &k);
        for(int j = 0; j < k; j++) {
            scanf("%d", &c);
            v[a].push_back(c);
        }
    }
    dfs(1, 1);
    int maxnum=-1;
    int maxdep=0;
    for(int i=1;i<=maxn;i++){
        if(num[i]>maxnum){
            maxnum=num[i];
            maxdep=i;
        }
    }
    printf("%d %d",maxnum,maxdep);
    return 0;
}

 

上一篇:Leetcode 1094. 拼车 (差分数组)


下一篇:1094 The Largest Generation (25 分)