A family hierarchy is usually presented by a pedigree tree where all the nodes on the same level belong to the same generation. Your task is to find the generation with the largest population.
Input Specification:
Each input file contains one test case. Each case starts with two positive integers N (<) which is the total number of family members in the tree (and hence assume that all the members are numbered from 01 to N), and M (<) which is the number of family members who have children. Then M lines follow, each contains the information of a family member in the following format:
ID K ID[1] ID[2] ... ID[K]
where ID
is a two-digit number representing a family member, K
(>) is the number of his/her children, followed by a sequence of two-digit ID
's of his/her children. For the sake of simplicity, let us fix the root ID
to be 01
. All the numbers in a line are separated by a space.
Output Specification:
For each test case, print in one line the largest population number and the level of the corresponding generation. It is assumed that such a generation is unique, and the root level is defined to be 1.
Sample Input:
23 13
21 1 23
01 4 03 02 04 05
03 3 06 07 08
06 2 12 13
13 1 21
08 2 15 16
02 2 09 10
11 2 19 20
17 1 22
05 1 11
07 1 14
09 1 17
10 1 18
Sample Output:
9 4
#include<bits/stdc++.h> using namespace std; const int maxn=1010; #define inf 0x3fffffff //vector<vector<int> > v;//此方式不能使用,因为存在某没有子节点的结点,但是v数组一位下标不存在 vector<int > v[100]; int num[maxn]; void dfs(int index,int depth){ num[depth]++; for(int i=0;i<v[index].size();i++){ dfs(v[index][i],depth+1); } } int main(){ fill(num,num+maxn,0); int n, m, a, k, c; scanf("%d %d", &n, &m); // v.resize(n); for(int i = 0; i < m; i++) { scanf("%d %d",&a, &k); for(int j = 0; j < k; j++) { scanf("%d", &c); v[a].push_back(c); } } dfs(1, 1); int maxnum=-1; int maxdep=0; for(int i=1;i<=maxn;i++){ if(num[i]>maxnum){ maxnum=num[i]; maxdep=i; } } printf("%d %d",maxnum,maxdep); return 0; }