知道两个文件的绝对目录,怎样计算出两个文件的相对目录,例如:知道
a = '/usr/share/pyshared/test/a.py'
b = '/usr/lib/dist/test/a.py' 可以直接应用OS模块中的os.path.reppath得到结果:
>>> print(os.path.relpath(a,b))
..\..\..\..\share\pyshared\test\a.py
但是计算结果是怎样实现的呢?
def _abspath_split(path):
abs = abspath(normpath(path))
prefix, rest = splitunc(abs)
is_unc = bool(prefix)
if not is_unc:
prefix, rest = splitdrive(abs)
return is_unc, prefix, [x for x in rest.split(sep) if x] def relpath(path, start=curdir):
"""Return a relative version of a path""" if not path:
raise ValueError("no path specified") start_is_unc, start_prefix, start_list = _abspath_split(start)
path_is_unc, path_prefix, path_list = _abspath_split(path) if path_is_unc ^ start_is_unc:
raise ValueError("Cannot mix UNC and non-UNC paths (%s and %s)"
% (path, start))
if path_prefix.lower() != start_prefix.lower():
if path_is_unc:
raise ValueError("path is on UNC root %s, start on UNC root %s"
% (path_prefix, start_prefix))
else:
raise ValueError("path is on drive %s, start on drive %s"
% (path_prefix, start_prefix))
# Work out how much of the filepath is shared by start and path.
i = 0
for e1, e2 in zip(start_list, path_list):
if e1.lower() != e2.lower():
break
i += 1 rel_list = [pardir] * (len(start_list)-i) + path_list[i:]
if not rel_list:
return curdir
return join(*rel_list)
上述代码是relpath在Python中的内部实现,实现比较复杂,作为简单的可替代形式:
def ownrelpath(a,b):
relpath = '';
la = a.split('/');
lb = b.split('/');
L = len(lb)-1;
tt = '';
for i in range(len(la)-1):
if la[i] == lb[i] and tt =='':
continue;
else:
tt = tt+la[i]+"\\";
relpath = "..\\"*(L-1);
print(relpath+tt);