【LeetCode】【算法】21. 合并两个有序链表
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public ListNode mergeTwoLists(ListNode list1, ListNode list2) {
ListNode dummyHead = new ListNode(0), cur = dummyHead;
while (list1 != null && list2 != null) {
if (list1.val < list2.val) {
cur.next = list1;
list1 = list1.next;
} else {
cur.next = list2;
list2 = list2.next;
}
cur = cur.next;
}
cur.next = list1 != null? list1: list2;
return dummyHead.next;
}
}