java使用链栈实现数制转换

java实现链栈在前面有所介绍:http://www.cnblogs.com/lixiaolun/p/4644141.html

将前面java实现链栈的代码稍作修改:

package linkedstack;

public class LinkStack {

	private Element base;
private Element top; class Element
{
public Object data;
public Element next;
} /**
* 初始化栈
* */
public void initStack()
{
top = new Element();
base = new Element();
top.data=null;
top.next=base;
base.data=null;
base.next=null;
} /**
* 入栈
* */
public void push(Object o)
{
Element e = new Element();
e.data = o;
if(top.next==base)//第一次入栈操作
{
e.next=base;
top.next=e;
}else
{
e.next=top.next;
top.next=e;
} } /**
* 出栈
* */
public Object pop()
{
Object o = null;
if(top.next==base)
{
System.out.println("栈中没有元素!");
return o;
}else
{
o = top.next.data;
//System.out.println("出栈操作"+o);
top.next=top.next.next;
}
return o;
}
/**
* 判断栈是否为空
* */
public Boolean isEmpty()
{
if(top.next==base)
{
return true;
}
return false;
}
/**
* 打印栈
* */
public void print()
{
System.out.print("打印栈:");
Element temp =top;
while(temp.next!=base)
{
System.out.print(temp.next.data+"\t");
temp =temp.next;
}
System.out.println();
}
}

  

java实现数制转换的类的代码:

package stackapplication;

import linkedstack.LinkStack;

public class Conversion {

	public static void main(String[] args) {
LinkStack lStack = new LinkStack();
lStack.initStack();
int N = 100;//原始十进制数
int X = 2;//要转化成X进制数
while(N!=0)
{
lStack.push(N%X);
N=N/X;
}
while(!lStack.isEmpty())
{
System.out.print(lStack.pop());
} }
}

  

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