1 //1.实现对逆波兰输入的表达式进行计算如(2-1)*(2+3)= 5 就输入2 1 - 2 3 + * //先把2 1 压栈 遇到-弹栈 再把2 3压进去 遇到+弹栈 最后遇到*弹栈 2 //2.支持带小数点的数据 3 例: 正常操作----->逆波兰表达式 4 a+b ------>a b + 5 a+(b-c)----->a b c - + 6 a+(b-c)*d--->a b c - d * + 7 a+d*(b-c)--->a d b c - * + 8 9 //2 5 + 4 2 - * == (2+5)*(4-2) == 14 10 //1 34 + 4 2 / * ==(1+34)*(4/2)== 70 11 #include<stdio.h> 12 #include<stdlib.h> 13 #include<ctype.h> //函数isdigit 检查是否为十进制数 14 15 #define MAXSIZE 100 16 #define MAXBUFFER 10 //缓冲区 17 18 typedef double ElemType; 19 20 typedef struct 21 { 22 ElemType *base; 23 ElemType *top; 24 int sizeStack; 25 }sqStack; 26 27 void InitStack(sqStack *s) 28 { 29 s->base = (ElemType *)malloc(MAXSIZE*sizeof(ElemType)); 30 if(!s->base) 31 { 32 exit(0); 33 } 34 s->top = s->base; 35 s->sizeStack = MAXSIZE; 36 } 37 38 void Push(sqStack *s,ElemType e) 39 { 40 if(s->top - s->base == s->sizeStack) 41 { 42 exit(0); 43 } 44 *(s->top) = e; 45 s->top++; 46 } 47 48 void Pop(sqStack *s,ElemType *e) 49 { 50 if(s->top == s->base) 51 { 52 return; 53 } 54 *e = *(--(s->top)); 55 } 56 57 int main(void) 58 { 59 sqStack s; 60 char c; 61 char str[MAXBUFFER]; 62 double d,e; 63 int i = 0; 64 65 InitStack(&s); 66 printf("请输入后缀表达式的字符,运算符与数字用空格隔开\n"); 67 scanf("%c",&c); 68 while(c != '#') 69 { 70 while(isdigit(c) || c=='.') //判断是否遇到数字 71 { 72 str[i++] = c; 73 str[i] = '\0'; 74 if(i >= 10) 75 { 76 printf("单个数字太大啊"); 77 return -1; 78 } 79 scanf("%c",&c); 80 if(c == ' ') 81 { 82 d = atof(str); //将字符串转换成浮点型 存在<stdlib.h> 83 Push(&s,d); 84 i = 0; 85 break; 86 } 87 } 88 89 switch(c) //判断是否遇到运算符 90 { 91 case '+': 92 Pop(&s,&e); 93 Pop(&s,&d); 94 Push(&s,d+e); 95 break; 96 case '-': 97 Pop(&s,&e); 98 Pop(&s,&d); 99 Push(&s,d-e); 100 break; 101 case '*': 102 Pop(&s,&e); 103 Pop(&s,&d); 104 Push(&s,d*e); 105 break; 106 case '/': 107 Pop(&s,&e); 108 Pop(&s,&d); 109 if(e != 0) 110 { 111 Push(&s,d/e); 112 } 113 else 114 { 115 printf("被除数不能为0!\n"); 116 return -1; 117 } 118 break; 119 } 120 scanf("%c",&c); 121 } 122 Pop(&s,&d); 123 printf("最终结果为:%f",d); 124 return 0; 125 } 126 127 128 129 //将中缀表达式转化为后缀表达式 130 #include<stdio.h> 131 #include<stdlib.h> 132 133 #define MAXSIZE 20 134 #define INCREMENTSIZE 10 135 136 typedef char ElemType; 137 typedef char ElemType2; 138 typedef struct 139 { 140 ElemType *base; 141 ElemType *top; 142 int StackSize; 143 }sqStack; 144 145 void InitStack(sqStack *s) 146 { 147 s->base = (ElemType *)malloc(MAXSIZE*sizeof(ElemType)); 148 if(!s->base) 149 { 150 printf("内存分配失败!\n"); 151 exit(0); 152 } 153 s->top = s->base; 154 s->StackSize = MAXSIZE; 155 } 156 157 void Push(sqStack *s, ElemType e) 158 { 159 if(s->top - s->base == s->StackSize) 160 { 161 s->base = (ElemType *)realloc(s->base,(s->StackSize+INCREMENTSIZE)*sizeof(ElemType)); 162 if(!s->base) 163 { 164 printf("重新分配内存失败!\n"); 165 exit(0); 166 } 167 s->top=s->base+s->StackSize; 168 s->StackSize=s->StackSize+INCREMENTSIZE; 169 } 170 *(s->top) = e; 171 s->top++; 172 } 173 174 void Pop(sqStack *s,ElemType *e) 175 { 176 if(s->top == s->base) 177 { 178 return; 179 } 180 *e = *(--(s->top)); 181 } 182 183 int StackLen(sqStack s) 184 { 185 return (s.top - s.base); 186 } 187 188 int main(void) 189 { 190 sqStack s; 191 char c,e; 192 193 InitStack(&s); 194 printf("请输入中缀表达式\n"); 195 scanf("%c",&c); 196 while(c !='#') 197 { 198 199 while(c>='0' && c<='9') 200 { 201 printf("%c",c); 202 scanf("%c",&c); 203 if(c<'0' || c>'9') 204 { 205 printf(" "); 206 } 207 } 208 209 if(c==')') 210 { 211 Pop(&s,&e); 212 while(e != '(') 213 { 214 printf("%c ",e); 215 Pop(&s,&e); 216 } 217 } 218 else if(c=='+' || c=='-') 219 { 220 if(!StackLen(s)) 221 { 222 Push(&s,c); 223 } 224 else 225 { 226 do 227 { 228 Pop(&s,&e); 229 if(e == '(') 230 { 231 Push(&s,e); //遇到左括号就弹走就ok 232 } 233 else 234 { 235 printf("%c ",e); 236 } 237 238 }while(StackLen(s) && e!='('); 239 Push(&s,c); 240 } 241 } 242 else if(c=='/' || c=='*' || c=='(') 243 { 244 Push(&s,c); 245 } 246 else if(c == '#') 247 { 248 break; 249 } 250 else 251 { 252 printf("数据输入错误啊!\n"); 253 return -1; 254 } 255 scanf("%c",&c); 256 } 257 while(StackLen(s)) 258 { 259 Pop(&s,&e); 260 printf("%c ",e); 261 } 262 return 0; 263 }