我对Autofac有疑问：
如何从容器中获取请求实例的类的名称？

是否有可能在创建对象时通过autofac将类“Autofac_Test”的名称传递给构造函数？

我的代码：

using System;
using System.Diagnostics;
using System.Reflection;
using Autofac;
using Xunit;

public class BootStrap
{
    public IContainer Configure()
    {
        var builder = new ContainerBuilder();
        builder.Register(b => new MyLogger(MethodBase.GetCurrentMethod().ReflectedType)).As<ILog>();
        return builder.Build();
    }
}
public class Autofac_Test
{
    private IContainer _containter;
    public Autofac_Test()
    {
        _containter = new BootStrap().Configure();
    }
    [Fact]
    public void Should_create_class_with_Name_BlaBla()
    {
        var logger = _containter.Resolve<ILog>();
        Assert.True(logger.Name == "Autofac_Test");
    }
}
public class MyLogger : ILog
{
    public string Name { get; private set; }
    public MyLogger(Type name)
    {
        Name = name.FullName;
    }
    public void Info(string message)
    {
        Debug.WriteLine(string.Format("{0} {1}", Name, message));
    }
}

public interface ILog
{
    void Info(string message);
    string Name { get; }
}

解决方法:

对于您的具体情况,获取此信息将非常困难.但正如我理解的那样,MyLogger需要知道它将被注入的类型名称以及代码示例可能不相关.

在这种情况下,您可以使用模块和准备事件：

public class LoggingModule : Autofac.Module
{
    protected override void AttachToComponentRegistration(
        IComponentRegistry componentRegistry, IComponentRegistration registration)
    {
        registration.Preparing += (sender, e) =>
        {
            Type limitType = e.Component.Activator.LimitType;
            e.Parameters = e.Parameters.Union(new[] {
                new ResolvedParameter((pi, c) => pi.ParameterType == typeof(ILogger), 
                                      (pi, c) => c.Resolve<ILogger>(new NamedParameter("name", limitType.Name))),
            });
        };
    }
}

然后你必须像这样注册你的模块：

ContainerBuilder builder = new ContainerBuilder();
builder.RegisterModule<LoggingModule>();
builder.RegisterType<MyLogger>().As<ILogger>();

现在,每次将ILogger注入类型时,它都将具有正确的名称.

class Foo
{
    public Foo(ILogger logger)
    {
        this._loggerName = logger.Name;
    }

    private readonly String _loggerName; 

    public String LoggerName 
    {
        get 
        {
            return this._loggerName;
        }
    }
}

LoggerName将是Foo.

您的测试现在看起来像这样：

[Fact]
public void Should_create_class_with_Name_BlaBla()
{
    var foo = _containter.Resolve<Foo>();
    Assert.AreEquals("foo", foo.LoggerName, "invalid loggerName");
}