android – Java jersey RESTful webservice请求

我一直在关注一个关于宁静服务的教程,它运行正常.然而,有一些我还不太了解的东西.这是它的样子:

@Path("/hello")
public class Hello {

    // This method is called if TEXT_PLAIN is request
    @GET
    @Produces( MediaType.TEXT_PLAIN )
    public String sayPlainTextHello() 
    {
        return "Plain hello!";
    }

    @GET
    @Produces( MediaType.APPLICATION_JSON )
    public String sayJsonTextHello() 
    {
        return "Json hello!";
    }

    // This method is called if XML is request
    @GET
    @Produces(MediaType.TEXT_XML)
    public String sayXMLHello() {
        return "<?xml version=\"1.0\"?>" + "<hello> Hello Jersey" + "</hello>";
    }

    // This method is called if HTML is request
    @GET
    @Produces(MediaType.TEXT_HTML)
    public String sayHtmlHello() 
    {
        return "<html> " + "<title>" + "Hello fittemil" + "</title>"
                + "<body><h1>" + "Hello!" + "</body></h1>" + "</html> ";
    }
} 

困扰我的是我无法利用正确的操作.当我从浏览器请求服务时,会调用相应的sayHtmlHello()方法.但是现在我正在开发一个Android应用程序,我希望在Json中得到结果.但是当我从应用程序调用该服务时,将调用MediaType.TEXT_PLAIN方法.我的android代码看起来与此类似:

Make an HTTP request with android

如何从我的Android应用程序中调用使用MediaType.APPLICATION_JSON的方法?
此外,我想使该特定方法返回一个对象,如果我在那里得到一些指导,那将是很好的.

解决方法:

我个人有使用Jersey在Java(JAX-RS)中实现REST的经验.然后我通过Android应用程序连接到这个RESTful Web服务.

在Android应用程序中,您可以使用HTTP Client库.它支持HTTP命令,如POST,PUT,DELETE,GET.例如,使用GET命令并以JSON格式或TextPlain传输数据:

public class Client {

    private String server;

    public Client(String server) {
        this.server = server;
    }

    private String getBase() {
        return server;
    }

    public String getBaseURI(String str) {
        String result = "";
        try {
            HttpParams httpParameters = new BasicHttpParams();
            int timeoutConnection = 3000;
            HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
            int timeoutSocket = 5000;
            HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);
            DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
            HttpGet getRequest = new HttpGet(getBase() + str);
            getRequest.addHeader("accept", "application/json");
            HttpResponse response = httpClient.execute(getRequest);
            result = getResult(response).toString();
            httpClient.getConnectionManager().shutdown();
        } catch (Exception e) {
            System.out.println(e.getMessage());
        } 
        return result;
    }

    public String getBaseURIText(String str) {
        String result = "";
        try {
            HttpParams httpParameters = new BasicHttpParams();
            int timeoutConnection = 3000;
            HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
            int timeoutSocket = 5000;
            HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);
            DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
            HttpGet getRequest = new HttpGet(getBase() + str);
            getRequest.addHeader("accept", "text/plain");
            HttpResponse response = httpClient.execute(getRequest);
            result = getResult(response).toString();
            httpClient.getConnectionManager().shutdown();
        } catch (Exception e) {
            System.out.println(e.getMessage());
        }
        return result;
    }

 private StringBuilder getResult(HttpResponse response) throws IllegalStateException, IOException {
            StringBuilder result = new StringBuilder();
            BufferedReader br = new BufferedReader(new InputStreamReader((response.getEntity().getContent())), 1024);
            String output;
            while ((output = br.readLine()) != null) 
                result.append(output);

            return result;      
      }
}

然后在Android类中,您可以:

Client client = new Client("http://localhost:6577/Example/rest/");
String str = client.getBaseURI("Example");    // Json format

解析JSON字符串(或者可能是xml)并在ListView,GridView和…中使用它

我简要介绍了你提供的链接.那里有一个好点.您需要在API级别11或更高级别的单独线程上实现网络连接.看看这个链接:HTTP Client API level 11 or greater in Android.

这是我在Client类中使用HTTP发布对象的方式:

public String postBaseURI(String str, String strUrl) {
        String result = "";
        try {
            HttpParams httpParameters = new BasicHttpParams();
            int timeoutConnection = 3000;
            HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
            int timeoutSocket = 5000;
            HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);
            DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
            HttpPost postRequest = new HttpPost(getBase() + strUrl);
            StringEntity input = new StringEntity(str);
            input.setContentType("application/json");
            postRequest.setEntity(input);
            HttpResponse response = httpClient.execute(postRequest);
            result = getResult(response).toString();
            httpClient.getConnectionManager().shutdown();
        } catch (Exception e) {
            System.out.println(e.getMessage());
        }
        return result;
    }

在REST WS中,我将对象发布到数据库:

    @POST
    @Path("/post")
    @Consumes(MediaType.APPLICATION_JSON)
    @Produces(MediaType.TEXT_PLAIN)
    public Response addTask(Task task) {        
        Session session = HibernateUtil.getSessionFactory().getCurrentSession();
        session.beginTransaction();
        session.save(task);
        session.getTransaction().commit();
        return Response.status(Response.Status.CREATED).build();
    }
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