简单的C++11线程池实现

线程池的C++11简单实现,源代码来自Github上作者progschj,地址为:A simple C++11 Thread Pool implementation,具体博客可以参见Jakob’s Devlog,地址为:A Thread Pool with C++11

1、线程池的实现代码如下:

ThreadPool.h

#ifndef THREAD_POOL_H
#define THREAD_POOL_H #include <vector>
#include <queue>
#include <memory>
#include <thread>
#include <mutex>
#include <condition_variable>
#include <future>
#include <functional>
#include <stdexcept> class ThreadPool {
public:
ThreadPool(size_t);
template<class F, class... Args>
auto enqueue(F&& f, Args&&... args)
-> std::future<typename std::result_of<F(Args...)>::type>;
~ThreadPool();
private:
// need to keep track of threads so we can join them
std::vector< std::thread > workers;
// the task queue
std::queue< std::function<void()> > tasks; // synchronization
std::mutex queue_mutex;
std::condition_variable condition;
bool stop;
}; // the constructor just launches some amount of workers
inline ThreadPool::ThreadPool(size_t threads)
: stop(false)
{
for(size_t i = 0;i<threads;++i)
workers.emplace_back(
[this]
{
for(;;)
{
std::function<void()> task; {
std::unique_lock<std::mutex> lock(this->queue_mutex);
this->condition.wait(lock,
[this]{ return this->stop || !this->tasks.empty(); });
if(this->stop && this->tasks.empty())
return;
task = std::move(this->tasks.front());
this->tasks.pop();
} task();
}
}
);
} // add new work item to the pool
template<class F, class... Args>
auto ThreadPool::enqueue(F&& f, Args&&... args)
-> std::future<typename std::result_of<F(Args...)>::type>
{
using return_type = typename std::result_of<F(Args...)>::type; auto task = std::make_shared< std::packaged_task<return_type()> >(
std::bind(std::forward<F>(f), std::forward<Args>(args)...)
); std::future<return_type> res = task->get_future();
{
std::unique_lock<std::mutex> lock(queue_mutex); // don't allow enqueueing after stopping the pool
if(stop)
throw std::runtime_error("enqueue on stopped ThreadPool"); tasks.emplace([task](){ (*task)(); });
}
condition.notify_one();
return res;
} // the destructor joins all threads
inline ThreadPool::~ThreadPool()
{
{
std::unique_lock<std::mutex> lock(queue_mutex);
stop = true;
}
condition.notify_all();
for(std::thread &worker: workers)
worker.join();
} #endif

2、基本的用法:

// create thread pool with 4 worker threads
ThreadPool pool(4); // enqueue and store future
auto result = pool.enqueue([](int answer) { return answer; }, 42); // get result from future
std::cout << result.get() << std::endl;

3、测试C++11线程池的例子程序如下:

example.cpp

#include <iostream>
#include <vector>
#include <chrono> #include "ThreadPool.h" int main()
{ ThreadPool pool(4);
std::vector< std::future<int> > results; for(int i = 0; i < 8; ++i) {
results.emplace_back(
pool.enqueue([i] {
std::cout << "hello " << i << std::endl;
std::this_thread::sleep_for(std::chrono::seconds(1));
std::cout << "world " << i << std::endl;
return i*i;
})
);
} for(auto && result: results)
std::cout << result.get() << ' ';
std::cout << std::endl; return 0;
}

编译运行example.cpp时需要添加C++11的支持,并且要加入pthread库的链接。

在Linux下的编译的命令为: g++ example.cpp -o example -std=c++11 -lpthread;如果在VS2017中使用,由于默认支持C++11,可以直接创建一个控制台程序,添加ThreadPool.h和example.cpp到项目,编译运行即可。

在Ubuntu18.10下测试如下:

havealex@havealex:~/GithubProjects/ThreadPool$ ls
COPYING example.cpp README.md ThreadPool.h
havealex@havealex:~/GithubProjects/ThreadPool$ g++ example.cpp -o example -std=c++11
/usr/bin/ld: /tmp/ccduRGse.o: in function `std::thread::thread<ThreadPool::ThreadPool(unsigned long)::{lambda()#1}, , void>(ThreadPool::ThreadPool(unsigned long)::{lambda()#1}&&)':
example.cpp:(.text._ZNSt6threadC2IZN10ThreadPoolC4EmEUlvE_JEvEEOT_DpOT0_[_ZNSt6threadC5IZN10ThreadPoolC4EmEUlvE_JEvEEOT_DpOT0_]+0x2f): undefined reference to `pthread_create'
collect2: error: ld returned 1 exit status
havealex@havealex:~/GithubProjects/ThreadPool$ g++ example.cpp -o example -std=c++11 -lpthread
havealex@havealex:~/GithubProjects/ThreadPool$ ls\
> ^C
havealex@havealex:~/GithubProjects/ThreadPool$ ls
COPYING example example.cpp README.md ThreadPool.h
havealex@havealex:~/GithubProjects/ThreadPool$ ./example
hello 0
hello 1
hello 2
hello 3
world 1
hello 4
world 0
hello 5
0 1 world 2
hello 6
4 world 3
hello 7
9 world 5
world 4
16 25 world 6
36 world 7
49

可以看出,结果的输出是无序并行的。

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