hdu 4891 模拟水题

http://acm.hdu.edu.cn/showproblem.php?pid=4891

给出一个文本,问说有多少种理解方式。

1. $$中间的,(s1+1) * (s2+1) * ...*(sn+1), si表示连续的空格数。

2.{}中间,即 | 的个数+1.

就是模拟

#include <iostream>
#include <cstring>
#include <cstdio>
#include <algorithm>
#include <vector>
#include <string>
#include <cmath>
using namespace std;
#define RD(x) scanf("%d",&x)
#define RD2(x,y) scanf("%d%d",&x,&y)
#define clr0(x) memset(x,0,sizeof(x))
typedef long long LL;
#define N 100005 int n;
string x , y; LL check(int l , int r){
LL ans = 1,tmp = 1;
for (int i=l;i<=r;++i){
if (x[i] == ' ')
++tmp;
else{
ans *= tmp;
tmp = 1;
if (ans > 100000)
return -1;
}
}
return ans;
} LL checkk(int l , int r){
LL ans = 1;
for (int i=l;i<=r;++i)
if (x[i] == '|') ++ans;
return ans;
} void work(){
getchar();
x = "";
while (n--){
getline(cin,y);
x += y;
}
int m = x.size();
LL ans = 1 , now;
for(int i = 0;i < m;){
while (x[i] != '$' && x[i] != '{' && i < m) ++i;
if (i == m) break;
int j = i+1;
if (x[i] == '$'){
while (x[j] != '$') ++j;
now = check(i,j);
} else {
while (x[j] != '}') ++j;
now = checkk(i,j);
}
if (now == -1){
puts("doge");
return;
}
ans *= now;
if (ans > 100000){
puts("doge");
return;
}
i = j+1;
}
printf("%I64d\n",ans);
} int main(){
while (~RD(n))
work();
return 0;
}
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