JSON转成List结构数据

先要引入对应的jar,然后调用net.sf.json库的


    ObjectMapper mapper = new ObjectMapper();
        JavaType javaType = mapper.getTypeFactory().constructParametricType(List.class, ApprWritUnionFormModel.class);
        /*List<FormModel> writUnionFormList = 
                JSON.parseArray(params, FormModel.class);*/
        List<FormModel> writUnionFormList=new ArrayList<FormModel>();
        try {
            writUnionFormList = (List<FormModel>)mapper.readValue(params, javaType);
        } catch (JsonParseException e) {
            e.printStackTrace();
        } catch (JsonMappingException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }


fastjson的简单用法,fastjson转换相对语法简单点,不过如果出现Bean类过大,或者在ie模式有时候会出现一些报错

List<FormModel> writUnionFormList = 
                JSON.parseArray(params, FormModel.class);

附录,如果在ie出现中文乱码问题,可以参考我之前教程:https://smilenicky.blog.csdn.net/article/details/100145430

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