考虑以下程序：

#include <stdio.h>
#include <time.h>

int main() {
  struct tm t;
  strptime("2015-08-13 12:00:00", "%F %T", &t);
  printf("t.tm_wday = %d\n", t.tm_wday);
  return 0;
}

在OSX下,这是我获得的：

$gcc test_strptime.c
$./a.out
t.tm_wday = 0

但是在Linux上,这是我得到的：

$gcc test_strptime.c
$./a.out
t.tm_wday = 4

行为为何不同？考虑到数据和一天中的时间,我希望星期几能够得到很好的定义？

解决方法:

strptime的Linux(glibc)和OS X实现不同.从OS X man page开始：

If the format string does not contain enough conversion specifications to completely specify the
resulting struct tm, the unspecified members of tm are left untouched. For example, if format is
“%H:%M:%S”, only tm_hour, tm_sec and tm_min will be modified.

与glibc相比：

The glibc implementation does not touch those fields which are not explicitly specified, except that it recomputes the tm_wday and tm_yday field if any of the year, month, or day elements changed.

因此,您可以说它按文档所述工作.