我正在编写一个简单的脚本来从here获取大灰色表.

我的代码如下：

import urllib2
from lxml import etree

html = urllib2.urlopen("http://www.afi.com/100years/movies10.aspx").read()

root = etree.XML(html)

但是我在最后一个声明中收到错误.

Traceback (most recent call last):
  File "D:\Workspace\afi100\afi100.py", line 13, in <module>
    root = etree.XML(html)
  File "lxml.etree.pyx", line 2720, in lxml.etree.XML (src/lxml/lxml.etree.c:52577)
  File "parser.pxi", line 1556, in lxml.etree._parseMemoryDocument (src/lxml/lxml.etree.c:79602)
  File "parser.pxi", line 1435, in lxml.etree._parseDoc (src/lxml/lxml.etree.c:78449)
  File "parser.pxi", line 943, in lxml.etree._BaseParser._parseDoc (src/lxml/lxml.etree.c:75099)
  File "parser.pxi", line 547, in lxml.etree._ParserContext._handleParseResultDoc (src/lxml/lxml.etree.c:71467)
  File "parser.pxi", line 628, in lxml.etree._handleParseResult (src/lxml/lxml.etree.c:72340)
  File "parser.pxi", line 568, in lxml.etree._raiseParseError (src/lxml/lxml.etree.c:71683)
XMLSyntaxError: Space required after the Public Identifier, line 3, column 59

任何想法如何解决这个错误？

谢谢.

解决方法:

您正在尝试使用XML解析器解析HTML,您应该使用lxml HTML解析器.

import urllib2
from StringIO import StringIO
from lxml import etree

ufile = urllib2.urlopen("http://www.afi.com/100years/movies10.aspx")

root = etree.parse(ufile, etree.HTMLParser())

print etree.tostring(root)