#函数需要⼀个参数

m1 = map(lambda x:x*x,[1,2,3])

print(list(m1))

#函数需要两个参数

m2 = map(lambda x,y:x+y,[1,2,3],[4,5,6])

print(list(m2))

def	f1(x,y):

    return	(x,y)

l1 = [0,1,2,3,4,5,6]

l2 = ['Sun','M','T','W','T','F','S']

l3 = map(f1,l1,l2)

print(list(l3))

[1, 4, 9]

[5, 7, 9]

[(0, 'Sun'), (1, 'M'), (2, 'T'), (3, 'W'), (4, 'T'), (5, 'F'), (6, 'S')]

from collections import Iterator

f1 = filter(lambda x:x%2, [1,2,3])

print(f1)

print(list(f1))

print(isinstance(f1, Iterator))

<filter object at 0x00000176DB8075C0>

[1, 3]

True

from functools import reduce

r1 = reduce(lambda x,y:x+y,[1,2,3,4])

r2 = reduce(lambda x,y:x+y,[1,2,3,4],5)

r3 = reduce(lambda x,y:x+y,['aa','bb','cc'],'dd')

print(r1)

print(r2)

print(r3)

10

15

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