子线程更新UI多个控件

线程里如果需要更新多个UI控件,怎么办
            Thread thread = new Thread(delegate()
            {
                Thread.Sleep(50);
                img = HttpOper(httpPath);
                if (pb.InvokeRequired)
                {

                    pb.Invoke(LoadPic,img);

                }
                else
                {
                    pb.Invoke(LoadPic);
                }
            });
            thread.Start();
这是一个基本的线程,PB是UI控件,如果我还有其它的控件也需要更新,难道是这样写
            Thread thread = new Thread(delegate()
            {
                Thread.Sleep(50);
                img = HttpOper(httpPath);
                if (pb.InvokeRequired)
                {

                    pb.Invoke(LoadPic,img);

                }
                else
                {
                    pb.Invoke(LoadPic);
                }
                if (pb1.InvokeRequired)
                {

                    pb1.Invoke(LoadPic,img);

                }
                else
                {
                    pb1.Invoke(LoadPic);
                }
                if (pb2.InvokeRequired)
                {

                    pb2.Invoke(LoadPic,img);

                }
                else
                {
                    pb2.Invoke(LoadPic);
                }
            });
            thread.Start();

------解决思路----------------------
你可以认为多个UI控件都属于同一个UI线程。因此,pb1.Invoke,和pb2.Invoke,和form1.Invoke没有本质的区别。
因此可以利用一个通用的函数,来把一个操作(Action)放到UI线程上去执行:


public partial class Form1 : Form
{
    public Form1()
    {
        InitializeComponent();
    }

    public void SendAction(Action action)
    {
        if (this.InvokeRequired)
        {
            this.Invoke(action);
        }
        else
        {
            action();
        }
    }

    void Test()
    {
        Thread thread = new Thread(delegate()
        {
            Thread.Sleep(50);
            img = HttpOper(httpPath);

            this.SendAction(() => { pb1.Image = img; });
            this.SendAction(() => { pb2.Image = img; });
        });
        thread.Start();
    }
}
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