我试图使用异步从URL列表中获取HTML(由ID标识).我需要使用代理.
我正在尝试使用aiohttp和下面的代理:
import asyncio
import aiohttp
from bs4 import BeautifulSoup
ids = ['1', '2', '3']
async def fetch(session, id):
print('Starting {}'.format(id))
url = f'https://www.testing.com/{id}'
async with session.get(url) as response:
return BeautifulSoup(await response.content, 'html.parser')
async def main(id):
proxydict = {"http": 'xx.xx.x.xx:xxxx', "https": 'xx.xx.xxx.xx:xxxx'}
async with aiohttp.ClientSession(proxy=proxydict) as session:
soup = await fetch(session, id)
if 'No record found' in soup.title.text:
print(id, 'na')
loop = asyncio.get_event_loop()
future = [asyncio.ensure_future(main(id)) for id in ids]
loop.run_until_complete(asyncio.wait(future))
根据这里的一个问题:https://github.com/aio-libs/aiohttp/pull/2582似乎ClientSession(proxy = proxydict)应该工作.
但是,我收到一个错误“__init __()得到一个意外的关键字参数’proxy’”
知道我该怎么做才能解决这个问题吗?
谢谢.
解决方法:
您可以在session.get调用中设置代理配置:
async with session.get(url, proxy=your_proxy_url) as response:
return BeautifulSoup(await response.content, 'html.parser')
如果您的代理需要身份验证,您可以将其设置在代理的网址中,如下所示:
proxy = 'http://your_user:your_password@your_proxy_url:your_proxy_port'
async with session.get(url, proxy=proxy) as response:
return BeautifulSoup(await response.content, 'html.parser')
要么:
proxy = 'http://your_proxy_url:your_proxy_port'
proxy_auth = aiohttp.BasicAuth('your_user', 'your_password')
async with session.get(url, proxy=proxy, proxy_auth=proxy_auth) as response:
return BeautifulSoup(await response.content, 'html.parser')
有关详细信息,请查看here